CoderByte Letter更改Java脚本

Question

问题是：

使用JavaScript，让函数LetterChanges(str)接受传递的str参数，并使用以下算法修改它。将字符串中的每个字母替换为字母表中紧跟其后的字母(即C变成d，z变成a)。然后大写这个新字符串中的每个元音(a，e，i，o，u)，最后返回这个修改后的字符串。

​

function LetterChanges(str){ 
  var result = "";
  for(var i = 0; i < str.length; i++) {
    var letters = str[i];
    if (letters == "a"|| letters == "e"|| letters == "i"|| letters == "o"|| letters =="u") {
      letters = letters.toUpperCase();
      result+=letters;
    } else if (letters == "z") {
      letters = "a";
    } else {
      var answer = "";
      var realanswer="";
      for (var i =0;i<str.length;i++) {
        answer += (String.fromCharCode(str.charCodeAt(i)+1));
      }              
      realanswer += answer
    }
  }
  return realanswer;
  return result;
}
LetterChanges();

​

基本上，如果返回realanswer放在返回结果之前，并且用"o“调用LetterChanges，我得到的输出是未定义的。但如果使用非元音调用，如"b“，它将输出"c”，这是正确的。

现在，如果我将return result放在return realanswer之前，它可以正确处理元音，但不能处理其他字母。谢谢你的帮助

Answer 1

    function LetterChanges(str) { 

      return str
        .replace(/[a-zA-Z]/g, (x) =>  String.fromCharCode(x.charCodeAt(0)+1))
        .replace(/[aeiou]/g, (v) => v.toUpperCase());
    }

1. 第一部分以1为增量修饰辅音。

- Regex is isolating the characters with `[]` versus no brackets at all. `g` ensures that the regex is applied anywhere in the string, as opposed to not putting `g` which gives you the first occurrence of the search. 
- You have to convert the characters in the string to their Unicode because incrementing is a math operation. `x.charCodeAt(0)` is saying at the index of 0 of the string in the argument. The increment of 1 is not within the parentheses but outside.

​

1. 第二部分将元音改为大写。

- This is pretty straightforward, the regex only finds the individual characters because `[]` are used, `g` for anywhere in the string. and the modifier is to make the characters become upper case.

​

Answer 2

 function LetterChanges(str) {
  var lstr = "";// Took a variable to store  after changing alphabet//

  for(var i=0;i<str.length;i++){
   var asVal = (str.charCodeAt(i)+1);// To convert string to Ascii value and 1 to it//
    lstr += (String.fromCharCode(asVal));// To convert back to string from Asii value//
  }
  console.log("Before converting vowels :"+lstr); //Printing in console changed alphabet//
  var neword =""; // variable to store word after changing vowels to uppercase// 
  for(i=0;i<lstr.length;i++){
    var strng = lstr[i]; // Storing every letter in strng variable while running loop //
    if(strng=="a"||strng=="e"||strng=="i"||strng=="o"||strng=="u"){
        neword += strng.toUpperCase(); // If it a vowel it gets uppercased and added //
       }
    else{
        neword += strng; // If not vowel , it just gets added without Uppercase //
    }

  }
  console.log("After converting vowels :"+neword); //Printing in console the word after captilising the vowels //
}

LetterChanges("Goutham"); // Calling a function with string Goutham //

Answer 3

function letterChanges(str) {
  let res = '';
  let arr = str.toLowerCase().split('');

  // Iterate through loop
  for(let i = 0; i < str.length; i++) {
    // Convert String into ASCII value and add 1
    let temp = str.charCodeAt(i) + 1;
    // Convert ASCII value back into String to the result
    res += (String.fromCharCode(temp));
  }
  console.log(res);
  // Replace only vowel characters to Uppercase using callback in the replace function
  return res.replace(/[aeiou]/g, (letters) {
      return letters.toUpperCase();
  });
}