我有4个int常量:
const int a1 = 1024;
const int a2 = 768;
const int b1 = 640;
const int b2 = 480;我想静态地检查它们是否有相同的比率。为了进行静态检查,我使用了BOOST_STATIC_ASSERT,但它不支持表达式。
我试过这个:
BOOST_STATIC_ASSERT( 1e-5 > std::abs( (double)a1 / (double)a2 - (double)b1 / (double)b2 ) );但这会产生下一个编译错误:
error: floating-point literal cannot appear in a constant-expression
error: 'std::abs' cannot appear in a constant-expression
error: a cast to a type other than an integral or enumeration type cannot appear in a constant-expression
error: a cast to a type other than an integral or enumeration type cannot appear in a constant-expression
error: a cast to a type other than an integral or enumeration type cannot appear in a constant-expression
error: a cast to a type other than an integral or enumeration type cannot appear in a constant-expression
error: a function call cannot appear in a constant-expression
error: template argument 1 is invalid如何修复上面的代码行才能使编译通过?
PS我不能访问c++0x特性和std::static_assert,这就是为什么我使用boost的静态断言。
发布于 2011-06-08 21:26:37
BOOST_STATIC_ASSERT(a1 * b2 == a2 * b1);发布于 2011-06-08 21:25:54
如何修复上面的代码行以使编译通过?
如果不求助于user763305对等式的优雅重写,你就不能。编译器是正确的:“浮点文字不能出现在常量表达式中”。此外,您也不能在常量表达式中调用函数(std::abs)。
C++0x将使用constexpr解决此问题。
https://stackoverflow.com/questions/6279410
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