我第一次在一个学校项目中使用Hibernate,我们正在为美食车构建一个类似Yelp的应用程序。但是,因为我首先创建了我的数据库模式,所以我使用Hibernate的逆向工程特性来生成Java类。但是,我不能让Hibernate以我想要的方式生成Java类。这是我的hibernate.reveng.xml文件
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-reverse-engineering PUBLIC "-//Hibernate/Hibernate Reverse Engineering DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-reverse-engineering-3.0.dtd">
<hibernate-reverse-engineering>
<schema-selection match-catalog="FoodTrucks"/>
<table-filter match-name="item"/>
<table-filter match-name="tags"/>
<table-filter match-name="truck"/>
<table-filter match-name="menu"/>
<table-filter match-name="tag_item_map" exclude="true"/>
<table-filter match-name="user"/>
<table-filter match-name="item_review"/>
<table-filter match-name="truck_review"/>
<table name="item">
<column name="menu_id" exclude="true"></column>
<foreign-key constraint-name="item_review_ibfk_2">
<many-to-one property="items"></many-to-one>
</foreign-key>
<foreign-key constraint-name="tag_item_map_ibfk_1">
<set property="tags"></set>
</foreign-key>
</table>
<table name="menu">
<column name="truck_id" exclude="true"></column>
<foreign-key constraint-name="item_ibfk_1">
<many-to-one property="items"></many-to-one>
</foreign-key>
</table>
<table name="tags">
<foreign-key constraint-name="tag_item_map_ibfk_2">
<many-to-one property="items"></many-to-one>
</foreign-key>
</table>
<table name="truck">
<foreign-key constraint-name="menu_ibfk_1">
<many-to-one property="menus"></many-to-one>
</foreign-key>
<foreign-key constraint-name="truck_review_ibfk_2">
<many-to-one property="reviews"></many-to-one>
</foreign-key>
</table>
<table name="user">
<column name="pass_word" exclude="true"></column>
<foreign-key constraint-name="item_review_ibfk_1">
<many-to-one property="itemReviews"></many-to-one>
</foreign-key>
<foreign-key constraint-name="truck_review_ibfk_1">
<many-to-one property="truckReviews"></many-to-one>
</foreign-key>
</table>
</hibernate-reverse-engineering>然而,我唯一能够正确完成的事情就是将标签排除到项目表中。例如,下面是生成的Item类,sans getters和setters。
public class Item implements java.io.Serializable {
private Integer id;
private Menu items;
private String itemName;
private double price;
private Set itemReviews = new HashSet(0);
public Item() {
}
public Item(String itemName, double price) {
this.itemName = itemName;
this.price = price;
}
public Item(Menu items, String itemName, double price, Set itemReviews) {
this.items = items;
this.itemName = itemName;
this.price = price;
this.itemReviews = itemReviews;
}
// getters and setters down here
}我知道我做错了什么或做错了什么,但我不知道是什么。此外,当我在初始生成后尝试生成代码时,我收到了这个错误消息“Hibernate configuration fails”,并显示以下消息:resource:/Item.hbm.xml‘t t the found see message.log for exception details。尽管Item.hbm.xml就在那里。
发布于 2016-03-08 01:54:57
你没有明确说明你想要怎样的Java类?
完全按照本教程进行操作-它将有助于理解https://netbeans.org/kb/docs/java/hibernate-java-se.ht ml的过程/步骤
https://stackoverflow.com/questions/35374687
复制相似问题