嗨,我有这个JS代码
function openPopup(url)
{
var newElem = new Element( 'div' );
newElem.setAttribute('rel','handler');
newElem.setAttribute('class','modal');
SqueezeBox.setContent( 'adopt', newElem );
SqueezeBox.setContent( 'iframe', url);
}这会用给定的SqueezeBox打开一个弹出式窗口。我想改变URL.I的大小怎么办?
发布于 2011-06-08 16:55:40
请尝试SqueezeBox.resize({x: 350,y: 400});
当然,您还必须调整内容的大小,如
SqueezeBox.initialize({
size: {x: 350, y: 400}
});
var newElem = new Element( 'div' );
newElem.appendText("Some Text");
newElem.setStyle('border', 'solid 2px black');
newElem.setStyle('width', '300px');
SqueezeBox.setContent('adopt', newElem);
SqueezeBox.resize({x: 750, y: 400})
newElem.setStyle('width', '700px'); https://stackoverflow.com/questions/6276205
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