使用Jax生成代理web服务客户端时出错

Question

我想知道我是否可以在下面的问题上得到一些帮助。

我尝试使用jax运行以下命令以生成web服务客户端代理：

wsimport http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL

但是我得到了以下错误：

Microsoft Windows [Version 6.1.7601]
Copyright (c) 2009 Microsoft Corporation.  All rights reserved.

C:\Users\Asher>wsimport http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL
parsing WSDL...


[WARNING] src-resolve.4.2: Error resolving component 's:schema'. It was detected that 's:schema' is in namespace 'http:/
/www.w3.org/2001/XMLSchema', but components from this namespace are not referenceable from schema document 'http://www.h
olidaywebservice.com/Holidays/HolidayService.asmx?WSDL#types?schema1'. If this is the incorrect namespace, perhaps the p
refix of 's:schema' needs to be changed. If this is the correct namespace, then an appropriate 'import' tag should be ad
ded to 'http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL#types?schema1'.
  line 15 of http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL#types?schema1

[ERROR] undefined element declaration 's:schema'
  line 15 of http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL

[ERROR] undefined element declaration 's:schema'
  line 36 of http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL

[ERROR] undefined element declaration 's:schema'
  line 74 of http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL

[ERROR] undefined element declaration 's:schema'
  line 97 of http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL

[ERROR] undefined element declaration 's:schema'
  line 120 of http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL

[ERROR] undefined element declaration 's:schema'
  line 131 of http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL


C:\Users\Asher>

首先，我是不是做错了什么？最后，如果没有办法生成代理客户端，那么有没有其他方法可以访问这个webservice &它是java中的方法。我是java的新手，所以如果有任何帮助，我将非常感激。

谢谢

Answer 1

您是如何创建该WSDL的？看起来您引用了一些未在WSDL中导出的数据类型。

编辑

wsdl引用了名为“%s”的架构，但找不到它，因为它的URL是

http://www.w3.org/2001/XMLSchema，但应该是

http://www.w3.org/2001/XMLSchema.xsd

更改后，现在它还会抱怨http://www.27seconds.com/Holidays/也没有指向模式。您需要在您的WSDL副本中修复所有它们，然后使用它执行wsimport。

我还访问了www.holidaywebservice.com，发现还有第二个版本：http://www.holidaywebservice.com/HolidayService_v2/HolidayService2.asmx?wsdl

Answer 2

您可以将XMLschema作为参数传递给wsimport

wsimport -b  http://www.w3.org/2001/XMLSchema.xsd  http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL

架构中存在潜在的架构名称冲突。一种解决方法是使用以下命令创建customization.xjb

<bindings xmlns="http://java.sun.com/xml/ns/jaxb" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xjc="http://java.sun.com/xml/ns/jaxb/xjc" version="2.0">
<globalBindings>
<xjc:simple/>
</globalBindings>
<bindings scd="~xsd:complexType">
<class name="ComplexTypeType"/>
</bindings>
<bindings scd="~xsd:simpleType">
<class name="SimpleTypeType"/>
</bindings>
<bindings scd="~xsd:group">
<class name="GroupType"/>
</bindings>
<bindings scd="~xsd:attributeGroup">
<class name="AttributeGroupType"/>
</bindings>
<bindings scd="~xsd:element">
<class name="ElementType"/>
</bindings>
<bindings scd="~xsd:attribute">
<class name="attributeType"/>
</bindings>
</bindings>

你的终极目标是

wsimport -b  http://www.w3.org/2001/XMLSchema.xsd -b customization.xjb  http://www.holidaywebservice.com/Holidays/HolidayService.asmx?WSDL