ActiveResource后缀

Question

使用ActiveResource，调用MyObject.find(id)会得到"self.site/self.prefix/:id.self.format“。我们需要访问"self.site/:id/self.suffix.self.format“而不是id.file_type。

ie:获取http://api_path/:id/tool.json

有没有办法为这个场景配置activeresource？我在文档中找不到太多。

Answer 1

ActiveResource::Base.element_path是创建路径的方法：

def element_path(id, prefix_options = {}, query_options = nil)
  prefix_options, query_options = split_options(prefix_options) if query_options.nil?
  "#{prefix(prefix_options)}#{collection_name}/#{URI.escape id.to_s}.#{format.extension}#{query_string(query_options)}"
end

我会创建一个重定义element_path的类，如下所示：

class CustomApiPath < ActiveResource::Base
  def element_path(id, prefix_options = {}, query_options = nil)
    prefix_options, query_options = split_options(prefix_options) if query_options.nil?
    "#{prefix(prefix_options)}#{URI.escape id.to_s}/#{collection_name}.#{format.extension}#{query_string(query_options)}"
  end
end

(警告:未测试)，然后其他ActiveResource模型将继承自CustomApiPath，而不是ActiveResource::Base。