我一直在尝试使用[UIDevice currentDevice ...]记录设备参数和NSLog。尽管尝试了不同的方法,但我总是得到相同的警告。
我得到的警告是:
Passing argument 1 of 'NSLog' from incompatible pointer type以下是我的所有尝试:
1:
NSString *UDID = [[UIDevice currentDevice] uniqueIdentifier];
NSString *deviceName = [[UIDevice currentDevice] name];
NSString *deviceModel = [[UIDevice currentDevice] model];
NSLog("\nDevice UDID: %@\nDevice Name: %@\nDevice Mode:%@\n",UDID, deviceName, deviceModel);2:
NSString *UDID = (NSString*)[[UIDevice currentDevice] uniqueIdentifier];
NSString *deviceName = (NSString*)[[UIDevice currentDevice] name];
NSString *deviceModel = (NSString*)[[UIDevice currentDevice] model];
NSLog("\nDevice UDID: %@\nDevice Name: %@\nDevice Mode:%@\n",UDID, deviceName, deviceModel);3:
NSString *UDID = [NSString stringWithFormat:[[UIDevice currentDevice] uniqueIdentifier]];
NSString *deviceName = [NSString stringWithFormat:[[UIDevice currentDevice] name]];
NSString *deviceModel = [NSString stringWithFormat:[[UIDevice currentDevice] model]];
NSLog("\nDevice UDID: %@\nDevice Name: %@\nDevice Mode:%@\n",UDID, deviceName, deviceModel);4:
NSLog("\nDevice UDID: %@\nDevice Name: %@\nDevice Mode:%@\n",[[UIDevice currentDevice] uniqueIdentifier], [[UIDevice currentDevice] name], [[UIDevice currentDevice] model]);有人能帮我吗?谢谢!
发布于 2011-05-24 02:20:11
您需要使用NSString作为NSLog的第一个参数,例如
NSLog(@"\nDevice UDID: %@\nDevice Name: %@\nDevice Mode:%@\n",UDID, deviceName, deviceModel);请注意字符串开头的'@‘
发布于 2011-05-24 02:20:05
NSLog接受NSString作为格式字符串,而不是const char*。在字符串前面加上一个@。
即:
NSLog(@"\nDevice UDID: %@\nDevice Name: %@\nDevice Mode:%@\n", ....发布于 2011-05-24 02:20:46
NSLog需要NSString作为其格式参数。您应该像这样调用NSLog:
NSLog(@"\nDevice UDID: %@", [[UIDevice currentDevice] uniqueIdentifier]);注意开头的"@“-这是一个常量的NSString引用。您使用的是纯C字符串。
https://stackoverflow.com/questions/6101201
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