Drupal6 Pager Stying - theme_pager问题“数组”

Question

我去了Drupal网站，找到了theme_pager的主题钩子，我从评论中复制了代码，做了一个离奇的艺术风格的分页程序，因为这接近于我需要的东西，尽管当我实现它时，我得到了

"1数组数组“

这是来自http://api.drupal.org/api/drupal/includes--pager.inc/function/theme_pager/6的代码

 function yourthemename_pager($tags = array(), $limit = 10, $element = 0, $parameters = array(), $quantity = 5) {
  global $pager_page_array, $pager_total;
  $tags = array("", "< prev", "", "next >", "");

 // Calculate various markers within this pager piece:
 // Middle is used to "center" pages around the current page.
 $pager_middle = ceil($quantity / 2);
 // current is the page we are currently paged to
 $pager_current = $pager_page_array[$element] + 1;
 // first is the first page listed by this pager piece (re quantity)
 $pager_first = $pager_current - $pager_middle + 1;
 // last is the last page listed by this pager piece (re quantity)
 $pager_last = $pager_current + $quantity - $pager_middle;
 // max is the maximum page number
 $pager_max = $pager_total[$element];
 // End of marker calculations.

 // Prepare for generation loop.
 $i = $pager_first;

 if ($pager_last > $pager_max) {
 // Adjust "center" if at end of query.
 $i = $i + ($pager_max - $pager_last);
 $pager_last = $pager_max;
 }

 if ($i <= 0) {
 // Adjust "center" if at start of query.
 $pager_last = $pager_last + (1 - $i);
 $i = 1;
 }
 // End of generation loop preparation.

 $li_previous = theme('pager_previous', (isset($tags[1]) ? $tags[1] : t('‹ previous')), $limit, $element, 1, $parameters);
 $li_next = theme('pager_next', (isset($tags[3]) ? $tags[3] : t('next ›')), $limit, $element, 1, $parameters);

 if ($pager_total[$element] > 1) {

      if ($li_previous) {
       $items[] = array(
        'class' => 'pager-previous',
        'data' => $li_previous,
       );
      }

// When there is more than one page, create the pager list.
if ($i != $pager_max) {
  // Now generate the actual pager piece.
  for (; $i <= $pager_last && $i <= $pager_max; $i++) {
    if ($i < $pager_current) {
  if ($pager_first > 1 && $i == $pager_first) {
   $output = '...'.$i;
   $stopPreEllipsis = true;
  } else {
   $output = $i;
  }
      $items[] = array(
        'class' => 'pager-item',
        'data' => theme('pager_previous', $output, $limit, $element, ($pager_current - $i), $parameters),
      );
    }
    if ($i == $pager_current) {
      $items[] = array(
        'class' => 'pager-current',
        'data' => $i,
      );
    }
    if ($i > $pager_current) {

  if ($pager_last < $pager_max && $i == $pager_last) {
   $output = $i.'...';
  } else {
   $output = $i;
  }

      $items[] = array(
        'class' => 'pager-item',
        'data' => theme('pager_next', $output, $limit, $element, ($i - $pager_current), $parameters),
      );
    }
  }
}
// End generation.
if ($li_next) {
  $items[] = array(
    'class' => 'pager-next',
    'data' => $li_next,
  );
}

return theme('item_list', $items, NULL, 'ul', array('class' => 'pager'));
  }
}

请帮帮忙。

理想情况下，我想要这样的寻呼机：

<1 2 3 4 5 6 7 8 9 10 >(所有的页码都带有next和previous) -但是如果我可以解决Array的这个问题，那么我应该能够修改代码。

谢谢詹姆斯

Answer 1

安装devel模块，将代码中的所有print语句替换为dpms。这样，您就可以知道数组的内容是什么，然后就可以打印所需的任何内容。