使用字符串操作将String[]拆分为2个String[]数组

Question

假设我有一个数组String[]，每个元素有47个字符。字符串的格式如下：

"My name is Fouad *6,#%$       , 67655-76       " // 30 characters for the name (It may contains special charaters) & ", " & 15 charaters for the phone-number

我想把每个元素分成两部分: name (去掉后面的空格，而不是中间的空格)& number (去掉后面的空格，而不是中间的空格)

所以我可以有两个数组String[]：name[]和number[]

我怎么做这样的算法呢？

Answer 1

public class Main
{
    public static void main (String [] args)
    {
        String [] array = new String []
        {
                "My name is Fouad *6,#%$       , 67655-76       ",
                "My name is Fouad *7,#%$       , 67655-77       ",
                "My name is Fouad *8,#%$       , 67655-78       ",
                "My name is Fouad *9,#%$       , 67655-79       ",
                "My name is Fouad *0,#%$       , 67655-70       ",
                "My name is Fouad *1,#%$       , 67655-71       "
        };

        String [] names = new String [array.length];
        String [] phones = new String [array.length];

        for (int i = 0; i < array.length; i++)
        {
            names [i] = array [i].substring (0, 30).trim ();
            phones [i] = array [i].substring (31).trim ();
        }

        for (String name : names) System.out.println (name);
        for (String phone : phones) System.out.println (phone);
    }
}

Answer 2

• 创建长度与原始数组相同的name[]和number[]
• 循环遍历数组
  1. 用namei填充arrayi.substring(0，使用arrayi.substring(30).trim()

填充namei

​

Answer 3

只需使用以下代码

"My name is Fouad *6,#%$       , 67655-76       ".substring(0,30).trim()
"My name is Fouad *6,#%$       , 67655-76       ".substring(30).trim()