Railstutorial.org帐簿，更改为嵌套路由

Question

您好，我一直在学习Rails教程中的内容，创建用户和帖子，以及显示帖子的提要。然而，作者从未使用过嵌套资源，这在rails中似乎非常重要，我想亲自了解如何使用它们。然而，当我根据Ruby on rails指南嵌套post资源时，它随后破坏了我所有的表单和路径。

我不想从头开始，而是希望更改为嵌套资源，并在此过程中准确地了解它们之间的区别。有没有人能帮我解决这个问题呢？谢谢你的帮助。

特别是我对如何处理提要感到困惑。目前，feed_item调用旧的post_path。

共享/_feed_item部分

<tr>
  <td class="avatar">
   <%= link_to avatar_for(feed_item.user), feed_item.user %>
  </td>
  <td class="post">
   <span class="title"><%= link_to feed_item.title, feed_item %></span><br />
   <span class="content">the plot: <%= feed_item.content %></span><br />
   <span class="timestamp">
   Posted <%= time_ago_in_words(feed_item.created_at) %> ago.
   </span>
 </td>
 </td>

   <% if current_user?(feed_item.user) %>
 <td>
  <%= link_to "delete", feed_item, :method => :delete,
                                  :confirm => "You sure?",
                                  :title => feed_item.content %>
 </td>
 <% end %>
</tr>

微柱控制器

class Micropost < ActiveRecord::Base
  .
  .
  .
  default_scope :order => 'microposts.created_at DESC'

  # Return microposts from the users being followed by the given user.
 scope :from_users_followed_by, lambda { |user| followed_by(user) }

  private

    # Return an SQL condition for users followed by the given user.
    # We include the user's own id as well.
    def self.followed_by(user)
      followed_ids = %(SELECT followed_id FROM relationships
                       WHERE follower_id = :user_id)
      where("user_id IN (#{followed_ids}) OR user_id = :user_id",
            { :user_id => user })
    end
end

它在本章http://ruby.railstutorial.org/chapters/user-microposts#top的11.3.3节中开始，并在本章http://ruby.railstutorial.org/chapters/following-users#top的12.3节中针对reals构建

Answer 1

以下是一些帮助您入门的链接：

Railscasts.com/episodes/139-嵌套资源

railscasts.com/episodes/196-nested-model-form-part-1

railscasts.com/episodes/197-nested-model-form-part-2