我不认为“最简单”是主观的。
寻找一个可托管的图片库,除了显示一个图像,并提供“下一个图像”和“前一个图像”,但所有不需要重新加载页面。显然,前置也会很好。PHP、Python、Ruby或JS。
发布于 2011-04-12 06:35:58
如果你想要简单,可以像这样?
<html>
<body>
<div>
<img id="image">
</img>
</div>
<table>
<tr>
<td onclick="getImage("previous");">Previous</td>
<td onclick="getImage("next");">Next</td>
</tr>
</table>
<script type="text/javascript">
counter = 0;
nextImage = new Image();
previousImage = new Image();
getImage = function(what) {
if (what === "previous") {counter--;}
else {counter++;}
nextImage.src = "http://www.example.com/image?data=" + (counter + 1);
previousImage.src = "http://www.example.com/image?data=" + (counter - 1);
document.getElementById("image").src = "http://www.example.com/image?data=" + counter;
}
</script>
</body>
</html>https://stackoverflow.com/questions/5628108
复制相似问题