我一直在开发一个使用DMVs来获取索引碎片信息的查询。
但是,该查询提供了比预期更多的结果。我认为问题出在joins中。
有什么想法吗?
select distinct '['+DB_NAME(database_id)+']' as DatabaseName,
'['+DB_NAME(database_id)+'].['+sch.name+'].['
+ OBJECT_NAME(ips.object_id)+']' as TableName,
i.name as IndexName,
ips.index_type_desc as IndexType,
avg_fragmentation_in_percent as avg_fragmentation,
SUM(row_count) as Rows
FROM
sys.indexes i INNER JOIN
sys.dm_db_index_physical_stats(NULL,NULL,NULL,NULL,'LIMITED') ips ON
i.object_id = ips.object_id INNER JOIN
sys.tables tbl ON tbl.object_id = ips.object_id INNER JOIN
sys.schemas sch ON sch.schema_id = tbl.schema_id INNER JOIN
sys.dm_db_partition_stats ps ON ps.object_id = ips.object_id
WHERE
avg_fragmentation_in_percent <> 0.0 AND ips.database_id = 6
AND OBJECT_NAME(ips.object_id) not like '%sys%'
GROUP BY database_id, sch.name, ips.object_id, avg_fragmentation_in_percent,
i.name, ips.index_type_desc
ORDER BY avg_fragmentation_in_percent desc发布于 2011-03-14 18:38:32
我认为你需要index_id来对抗sys.dm_db_partition_stats和sys.indexes。
使用sys.dm_db_index_physical_stats的第一个参数来过滤db可能比使用where子句ips.database_id = 6更好。
我不理解distinct、group by或sum(row_count)条款。
以下是一个查询,您可以尝试并查看它是否执行了您想要的操作。
select
db_name(ips.database_id) as DataBaseName,
object_name(ips.object_id) as ObjectName,
sch.name as SchemaName,
ind.name as IndexName,
ips.index_type_desc,
ps.row_count
from sys.dm_db_index_physical_stats(6,NULL,NULL,NULL,'LIMITED') as ips
inner join sys.tables as tbl
on ips.object_id = tbl.object_id
inner join sys.schemas as sch
on tbl.schema_id = sch.schema_id
inner join sys.indexes as ind
on ips.index_id = ind.index_id and
ips.object_id = ind.object_id
inner join sys.dm_db_partition_stats as ps
on ps.object_id = ips.object_id and
ps.index_id = ips.index_id and
ps.partition_number = ips.partition_numberhttps://stackoverflow.com/questions/5296226
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