我知道这个关于声音的问题现在已经被问了几次了,相信我,我已经看过了,试图找到我自己的答案。我之前在一个不同的项目中使用Java的声音工作,没有任何困难,使用以下代码:
public void playWelcome (){
try{
InputStream inputStream =
getClass().getResourceAsStream("Start.wav");
AudioStream audioStream = new AudioStream(inputStream);
AudioPlayer.player.start(audioStream);
}catch(IOException ioException){
ioException.printStackTrace();
System.out.println("Unable to Find WAV/Start FIle");
}
} 显然,这并不像之前解释的那样工作,所以我尝试使用:
public void uploadDownload() {
try {
AudioInputStream audioInputStream =
AudioSystem.getAudioInputStream(new
File("/DaWord/src/resources/upload.wav").getAbsoluteFile());
Clip clip = AudioSystem.getClip();
clip.open(audioInputStream);
clip.start();
} catch(Exception ex) {
System.out.println("Error with playing sound.");
ex.printStackTrace();
}
}注意:我也尝试过不带斜杠的文件。'my file.wav‘有人能帮我一下吗?
更新:
所以我设法让它运行起来..某种程度上:
文件soundFile =新文件(“/Users/myname/DaWord/src/testing.wav”);
AudioInputStream audioIn = AudioSystem.getAudioInputStream(soundFile);
// Get a sound clip resource.
Clip clip = AudioSystem.getClip();
// Open audio clip and load samples from the audio input stream.
clip.open(audioIn);
clip.start();但是有没有人知道如何通过不提供绝对路径来做到这一点呢?我尝试在文件的末尾使用.absoulutePath();,例如: File
文件=新文件("sound.wav").absouloutePath();
发布于 2016-01-29 02:40:41
正如here所解释的,这是分配来自文件或AudioInputStream的管道的方法:
// from a wave File
File soundFile = new File("eatfood.wav");
AudioInputStream audioIn = AudioSystem.getAudioInputStream(soundFile);
// from a URL
URL url = new URL("http://www.zzz.com/eatfood.wav");
AudioInputStream audioIn = AudioSystem.getAudioInputStream(url);
// can read from a disk file and also a file contained inside a JAR (used for distribution)
// recommended
URL url = this.getClass().getClassLoader().getResource("eatfood.wav");
AudioInputStream audioIn = AudioSystem.getAudioInputStream(url);发布于 2016-01-30 03:07:52
这暂时是可行的.具有完整路径
File("/Users/mrBerns/NetBeansProjects/DaWord/src/ching.wav");soundFile =新文件
AudioInputStream audioIn = AudioSystem.getAudioInputStream(soundFile);
// Get a sound clip resource.
Clip clip = AudioSystem.getClip();
// Open audio clip and load samples from the audio input stream.
clip.open(audioIn);
clip.start();https://stackoverflow.com/questions/35069190
复制相似问题