我的表中有几行,我想将最后一个单词从一列导出到新列中。
只需要从这个字符串中拆分出最后一个单词,不知道怎么做……
UPDATE sc_module_template_slideshows_images
SET image_title = RIGHT(image_name, ?????)这只是一个猜测,任何函数都可以。MYSQL 5.
以下是我的数据集的一个示例:
|| *slideshow_id* || *image_id* || *image_active* || *image_order* || *image_name* || *image_source* || *image_link* || *image_logo* || *image_title* || *image_presented* || *image_position* ||
|| 1 || 1 || 1 || 1 || Lurex Cotton Lappato || media/products/Porcelain/Collections/Lurex/Swatches/Lurex Cotton Lappato.jpg || || || || || ||
|| 1 || 2 || 1 || 2 || Lurex Cotton Squadrato || media/products/Porcelain/Collections/Lurex/Swatches/Lurex Cotton Squadrato.jpg || || || || || ||
|| 2 || 3 || 1 || 3 || Lurex Flax Lappato || media/products/Porcelain/Collections/Lurex/Swatches/Lurex Flax Lappato.jpg || || || || || ||
|| 2 || 4 || 1 || 4 || Lurex Flax Squadrato || media/products/Porcelain/Collections/Lurex/Swatches/Lurex Flax Squadrato.jpg || || || || || ||
|| 3 || 5 || 1 || 5 || Lurex Lame Lappato || media/products/Porcelain/Collections/Lurex/Swatches/Lurex lame Lappato.jpg || || || || || ||
|| 3 || 6 || 1 || 6 || Lurex Lame Squadrato || media/products/Porcelain/Collections/Lurex/Swatches/Lurex Lame Squadrato.jpg || || || || || ||
|| 4 || 7 || 1 || 7 || Lurex Modal Lappato || media/products/Porcelain/Collections/Lurex/Swatches/Lurex Modal Lappato.jpg || || || || || ||
|| 4 || 8 || 1 || 8 || Lurex Modal Squadrato || media/products/Porcelain/Collections/Lurex/Swatches/Lurex Modal Squadrato.jpg || || || || || ||发布于 2011-02-28 10:32:50
SUBSTRING_INDEX是正确的函数:
SET image_title = SUBSTRING_INDEX(image_name,' ',-1)发布于 2011-02-28 10:32:45
SET image_title = SUBSTRING_INDEX(image_name, ' ', -1);发布于 2011-02-28 10:33:50
您可以使用substring_index()函数。
示例
select substring_index('Lurex Cotton Lappato',' ',-1); -- Lappato将其应用于update子句。
https://stackoverflow.com/questions/5137679
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