NSString操作

Question

我想像这样操作NSString

(0)喜欢(1)。(请参见。(2)

(0) =拉曼

(1) =你

(2) = ThisGift

至

拉曼喜欢你。(请参见。ThisGift)

我不知道什么方法可以解决这个问题。

提前感谢，致以敬意

文卡特。

Answer 1

-[NSString stringByReplacingOccurrencesOfString:withString:]。

您可以这样使用它：

NSString * source = @"(0) Likes (1). (see. (2))";
source = [source stringByReplacingOccurrencesOfString:@"(0)" withString:@"Raman"];
NSLog(@"%@", source);  //logs "Raman Likes (1). (see. (2))"

Answer 2

如果允许您更改模板格式，则可以使用format strings。

NSString *template1 = @"%1$@ Likes %2$@. (see. %3$@)",
         *template2 = @"%2$@ got a %3$@ from %1$@.";
NSString *msg1 = [NSString stringWithFormat:template1,@"Raman",@"You",@"ThisGift"],
         *msg2 = [NSString stringWithFormat:template2,@"Raman",@"You",@"ThisGift"];

或者(如果格式字符串可以始终依赖于参数的替换顺序)：

NSString *template = @"%@ Likes %@. (see. %@)";
NSString *msg = [NSString stringWithFormat:template,@"Raman",@"You",@"ThisGift"];

Answer 3

请参阅-[NSString stringByReplacingOccurrencesOfString:withString:]

NSString *foo = @"(0) likes (1). (see (2))";
NSString *bar;
bar = [foo stringByReplacingOccurrencesOfString:@"(0)"
                                     withString:@"Raman"];
bar = [bar stringByReplacingOccurrencesOfString:@"(1)"
                                     withString:@"You"];
bar = [bar stringByReplacingOccurrencesOfString:@"(2)"
                                     withString:@"ThisGift"];