在android中解析本地XML文件

Question

大家好，我是sowmya，我是android的新手，请任何人能帮助我，我正在解析以下本地xml文件，但我只得到了第一个问题(第一组标签)的输出，但第二个问题(重复的标签)我没有得到，，谢谢提前

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<innertag sampleattribute="innertagAttribute">
<mytag>1)  How did u find the hotel house keeping overall in the year  </mytag>

    <innertag sampleattribute="innertagAttribute">
<mytag>2)  How do u rate the hotel house keeping overall in the year  </mytag>

</outertag>

////////////////////////////////////////////////////////////////////////////////////////////正在将其用作xml处理程序文件////////////////////////////////////////////////////////////////////////////////////////包com.itwine；

导入org.xml.sax.Attributes；导入org.xml.sax.SAXException；导入org.xml.sax.helpers.DefaultHandler；

公共类XMLHandler扩展了DefaultHandler{

 // ===========================================================
 // Fields
 // ===========================================================

 private boolean in_outertag = false;
 private boolean in_innertag = false;
 private boolean in_mytag = false;




 private boolean in_innertag1 = false;
 private boolean in_mytag1= false;




 private boolean in_innertag2 = false;
 private boolean in_mytag2 = false;

 private XMLDataSet myParsedExampleDataSet = new XMLDataSet();
 private XMLDataSet myParsedExampleDataSet1 = new XMLDataSet();
 private XMLDataSet myParsedExampleDataSet2 = new XMLDataSet();
 private XMLDataSet myParsedExampleDataSet3 = new XMLDataSet();


 // ===========================================================
 // Getter & Setter
 // ===========================================================

 public XMLDataSet getParsedData() {
      return this.myParsedExampleDataSet;
 }

 public XMLDataSet getParsedData1() {
     return this.myParsedExampleDataSet1;
}
 public XMLDataSet getParsedData2() {
     return this.myParsedExampleDataSet2;
}
 public XMLDataSet getParsedData3() {
     return this.myParsedExampleDataSet3;
}


 // ===========================================================
 // Methods
 // ===========================================================
 @Override
 public void startDocument() throws SAXException {
      this.myParsedExampleDataSet = new XMLDataSet();

      this.myParsedExampleDataSet1 = new XMLDataSet();

      this.myParsedExampleDataSet2 = new XMLDataSet();

      this.myParsedExampleDataSet3 = new XMLDataSet();
 }

 @Override
 public void endDocument() throws SAXException {
      // Nothing to do
 }

 /** Gets be called on opening tags like:
  * <tag>
  * Can provide attribute(s), when xml was like:
  * <tag attribute="attributeValue">*/
 @Override
 public void startElement(String namespaceURI, String localName,
           String qName, Attributes atts) throws SAXException {
      if (localName.equals("outertag")) 
      {
           this.in_outertag = true;
      }



      else if (localName.equals("innertag"))
      {
           this.in_innertag = true;
      }

      else if (localName.equals("mytag")) 
      {
           this.in_mytag = true;
      }

      else if (localName.equals("tagwithnumber")) 
      {
           // Extract an Attribute
           String attrValue = atts.getValue("thenumber");
           int i = Integer.parseInt(attrValue);
           myParsedExampleDataSet.setExtractedInt(i);
      }

      else if (localName.equals("innertag1"))
      {
           this.in_innertag1 = true;
      }

      else if (localName.equals("mytag1")) 
      {
           this.in_mytag1 = true;
      }

      else if (localName.equals("tagwithnumber1")) 
      {
           // Extract an Attribute
           String attrValue = atts.getValue("thenumber");
           int j = Integer.parseInt(attrValue);
           myParsedExampleDataSet1.setExtractedInt(j);
      }

      else if (localName.equals("innertag2"))
      {
           this.in_innertag2 = true;
      }

      else if (localName.equals("mytag2")) 
      {
           this.in_mytag2 = true;
      }

      else if (localName.equals("tagwithnumber2")) 
      {
           // Extract an Attribute
           String attrValue = atts.getValue("thenumber");
           int k = Integer.parseInt(attrValue);
           myParsedExampleDataSet2.setExtractedInt(k);
      }

      else if (localName.equals("QIA")) 
      {
           // Extract an Attribute



      }


 }


 /** Gets be called on closing tags like:
  * </tag> */
 @Override
 public void endElement(String namespaceURI, String localName, String qName)
           throws SAXException {



      if (localName.equals("outertag")) 
      {
           this.in_outertag = false;
      }
      else if (localName.equals("innertag")) 

      {
           this.in_innertag = false;
      }

      else if (localName.equals("mytag")) 

      {
           this.in_mytag = false;
      }

      else if (localName.equals("tagwithnumber")) {
           // Nothing to do here
      }


      else if (localName.equals("innertag1")) 

      {
           this.in_innertag1 = false;
      }

      else if (localName.equals("mytag1")) 

      {
           this.in_mytag1 = false;
      }

      else if (localName.equals("tagwithnumber1")) {
           // Nothing to do here
      }

      else if (localName.equals("innertag2")) 

      {
           this.in_innertag2 = false;
      }

      else if (localName.equals("mytag2")) 

      {
           this.in_mytag2 = false;
      }

      else if (localName.equals("tagwithnumber2")) {
           // Nothing to do here
      }
 }


 /** Gets be called on the following structure:
  * <tag>characters</tag> */
 @Override
public void characters(char ch[], int start, int length) {
      if(this.in_mytag){
      myParsedExampleDataSet.setExtractedString(new String(ch, start, length));
 }

      else if(this.in_mytag1){
          myParsedExampleDataSet1.setExtractedString(new String(ch, start, length));
     }

      else if(this.in_mytag2){
          myParsedExampleDataSet2.setExtractedString(new String(ch, start, length));
     }
}

}

Answer 1

我已经在android中完成了xml解析。检查此链接以获取内部版本..

compliantbox.com/XmlParsingcompliant.zip

只需将该url替换为您的本地地址...................

Answer 2

你代码中的实现是这样的，如果条件为真，它在第一个instance..so出现，你的代码看不到第二个mytag。

如果允许更改，您可以很好地更改标记名称：

mytag11

mytag22

我想，这应该行得通。