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如何处理Python xmlrpclib连接被拒绝?
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Stack Overflow用户
提问于 2011-01-15 06:24:52
回答 1查看 7.1K关注 0票数 5

我不知道我到底做错了什么,我写了一个试图连接到一个不存在的服务器的RPC客户端,我试图处理抛出的异常,但无论我尝试什么,我都不知道我应该如何处理:

代码语言:javascript
复制
def _get_rpc():
    try:
        a = ServerProxy('http://dd:LNXFhcZnYshy5mKyOFfy@127.0.0.1:9001')
        a = a.supervisor
        return a
    except:
        return False

rpc = _get_rpc()
if not rpc:
    print "No RPC"

因为没有服务器在运行,所以我希望输出是"No RPC“,但我得到了一个异常:

代码语言:javascript
复制
Traceback (most recent call last):
  File "xmlrpctest.py", line 20, in <module>
    if not rpc:
  File "/usr/lib/python2.6/xmlrpclib.py", line 1199, in __call__
    return self.__send(self.__name, args)
  File "/usr/lib/python2.6/xmlrpclib.py", line 1489, in __request
    verbose=self.__verbose
  File "/usr/lib/python2.6/xmlrpclib.py", line 1235, in request
    self.send_content(h, request_body)
  File "/usr/lib/python2.6/xmlrpclib.py", line 1349, in send_content
    connection.endheaders()
  File "/usr/lib/python2.6/httplib.py", line 908, in endheaders
    self._send_output()
  File "/usr/lib/python2.6/httplib.py", line 780, in _send_output
    self.send(msg)
  File "/usr/lib/python2.6/httplib.py", line 739, in send
    self.connect()
  File "/usr/lib/python2.6/httplib.py", line 720, in connect
    self.timeout)
  File "/usr/lib/python2.6/socket.py", line 561, in create_connection
    raise error, msg
socket.error: [Errno 111] Connection refused
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2011-03-25 04:32:30

_get_rpc返回对未连接的ServerProxy的supervisor方法的引用。异常不会发生在您处理它的_get_rpc调用中;它发生在您尝试评估此supervisor方法时(在"if not rpc“中)。从交互式提示符处尝试:

代码语言:javascript
复制
Python 2.6.5 (r265:79063, Apr 16 2010, 13:57:41) 
[GCC 4.4.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import xmlrpclib
>>> xmlrpclib.ServerProxy("http://127.0.0.1");
<ServerProxy for 127.0.0.1/RPC2>
>>> xmlrpclib.ServerProxy("http://127.0.0.1").supervisor;
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.6/xmlrpclib.py", line 1199, in __call__
    return self.__send(self.__name, args)
  File "/usr/lib/python2.6/xmlrpclib.py", line 1489, in __request
    verbose=self.__verbose
  File "/usr/lib/python2.6/xmlrpclib.py", line 1243, in request
    headers
xmlrpclib.ProtocolError: <ProtocolError for 127.0.0.1/RPC2: 404 Not Found>
>>> foo = xmlrpclib.ServerProxy("http://127.0.0.1");
>>> dir (foo)
['_ServerProxy__allow_none', '_ServerProxy__encoding', '_ServerProxy__handler', '_ServerProxy__host', '_ServerProxy__request', '_ServerProxy__transport', '_ServerProxy__verbose', '__doc__', '__getattr__', '__init__', '__module__', '__repr__', '__str__']
>>> foo.supervisor
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.6/xmlrpclib.py", line 1199, in __call__
    return self.__send(self.__name, args)
  File "/usr/lib/python2.6/xmlrpclib.py", line 1489, in __request
    verbose=self.__verbose
  File "/usr/lib/python2.6/xmlrpclib.py", line 1243, in request
    headers
xmlrpclib.ProtocolError: <ProtocolError for 127.0.0.1/RPC2: 404 Not Found>
>>> bar = foo.supervisor
>>> bar
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.6/xmlrpclib.py", line 1199, in __call__
    return self.__send(self.__name, args)
  File "/usr/lib/python2.6/xmlrpclib.py", line 1489, in __request
    verbose=self.__verbose
  File "/usr/lib/python2.6/xmlrpclib.py", line 1243, in request
    headers
xmlrpclib.ProtocolError: <ProtocolError for 127.0.0.1/RPC2: 404 Not Found>

请注意,在尝试计算.supervisor方法(ServerProxy(...).supervisor、foo.supervisor或bar)时,您是如何看到异常的,而不是在将其分配到其他地方时(bar = foo.supervisor)。

票数 4
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/4696642

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