安卓FileOutputStream

Question

我尝试使用"openFileOutput“保存一个图像文件，然后使用EXTRA_STREAM将该文件添加到我的意图中。但是logcat一直说文件大小为0，我在我的清单中有适当的权限。

FileOutputStream fos = openFileOutput("p001.jpg", Context.MODE_WORLD_READABLE);
         File jpg = getFileStreamPath("p001.jpg");
            fos.close();
            Intent share = new Intent(android.content.Intent.ACTION_SEND);



         share.setType("image/jpeg");
            share.putExtra(Intent.EXTRA_SUBJECT, "Fail picture");
            share.putExtra(Intent.EXTRA_TEXT, "Epic fail!!!");
            share.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(jpg)); 
            startActivity(Intent.createChooser(share, "Choose share method."));

更新的代码

private void HandleSMS() throws IOException {
         FileOutputStream fos = openFileOutput(R.drawable.p001, Context.MODE_WORLD_READABLE);
             File jpg = getFileStreamPath("p001.jpg");

            fos.close();
            Intent share = new Intent(android.content.Intent.ACTION_SEND);



         share.setType("image/jpeg");
            share.putExtra(Intent.EXTRA_SUBJECT, "Fail picture");
            share.putExtra(Intent.EXTRA_TEXT, "Epic fail!!!");
            share.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(jpg)); 
            startActivity(Intent.createChooser(share, "Choose share method."));


        }

Answer 1

因此，只需做一件事，而不是使用R.drawable.NameOfTheImage直接命名。