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"No Persistence provider for EntityManager“错误
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Stack Overflow用户
提问于 2010-11-24 06:04:20
回答 6查看 22.8K关注 0票数 5

我是JPA的新手,我试着从书中做一个简单的例子。但无论我做什么,我都会收到以下错误:

代码语言:javascript
复制
Exception in thread "main" javax.persistence.PersistenceException: No Persistence provider for EntityManager named EmployeeService
        at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:89)
        at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:60)
        at com.mycompany.simpleentity.EmployeeTest.main(EmployeeTest.java:18)

我用谷歌搜索了很多,我做了所有我读到的关于JPA的事情。

以下是我的项目的目录树:

代码语言:javascript
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    .
|-- pom.xml
`-- src
    |-- main
    |   |-- java
    |   |   `-- com
    |   |       `-- mycompany
    |   |           `-- simpleentity
    |   |               |-- Employee.java
    |   |               |-- EmployeeService.java
    |   |               `-- EmployeeTest.java
    |   `-- resources
    |       `-- META-INF
    |           `-- persistence.xml
    `-- test

这是我的pom.xml:

代码语言:javascript
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<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
  <modelVersion>4.0.0</modelVersion>
  <groupId>com.mycompany</groupId>
  <artifactId>SimpleEntity</artifactId>
  <packaging>jar</packaging>
  <version>1.0-SNAPSHOT</version>
  <name>SimpleEntity</name>
  <url>http://maven.apache.org</url>
  <dependencies>
    <dependency>
      <groupId>junit</groupId>
      <artifactId>junit</artifactId>
      <version>3.8.1</version>
      <scope>test</scope>
    </dependency>
    <dependency>
      <groupId>javax.persistence</groupId>
      <artifactId>persistence-api</artifactId>
      <version>1.0</version>      
    </dependency>
    <dependency>
        <groupId>postgresql</groupId>
        <artifactId>postgresql</artifactId>
        <version>9.0-801.jdbc4</version>
    </dependency>
  </dependencies>

  <build>

      <plugins>
        <plugin>
          <groupId>org.apache.maven.plugins</groupId>
          <artifactId>maven-compiler-plugin</artifactId>
          <configuration>
             <source>1.5</source>
             <target>1.5</target>
          </configuration>
        </plugin>

        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-jar-plugin</artifactId>

            <configuration>
                <archive>
                    <manifest>
                        <addClasspath>true</addClasspath>
                        <mainClass>com.mycompany.simpleentity.EmployeeTest</mainClass>
                        <!-- <classpathLayoutType>repository</classpathLayoutType> -->
                        <classpathMavenRepositoryLayout>true</classpathMavenRepositoryLayout>
                        <classpathPrefix>${env.HOME}/.m2/repository</classpathPrefix>

                    </manifest>
                </archive>
            </configuration>
        </plugin>
      </plugins>

  </build> 
</project>

这是我的源代码: EmployeeTest.java:

代码语言:javascript
复制
package com.mycompany.simpleentity;

import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;

public class EmployeeTest {
    public static void main(String[] args) {
        EntityManagerFactory emf = Persistence.createEntityManagerFactory("EmployeeService");
        EntityManager em = emf.createEntityManager();

    }
}

这是我的persistance.xml

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复制
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
        http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"
        version="1.0">

    <persistence-unit name="EmployeeService" transaction-type="RESOURCE_LOCAL">
        <class>com.mycompany.simpleentity.Employee</class>
        <properties>
            <property name="toplink.jdbc.driver"
                      value="org.postgresql.Driver"/>
            <property name="toplink.jdbc.url"
                      value="jdbc:postgresql://localhost:5432/testdb;create=true"/>
            <property name="toplink.jdbc.user" value="postgres"/>
            <property name="toplink.jdbc.password" value="111"/>

        </properties>
    </persistence-unit>
</persistence>

我做错了什么?提前谢谢你。

EN

回答 6

Stack Overflow用户

回答已采纳

发布于 2010-11-24 06:22:59

JPA是由多个JPA提供者(Hibernate、EclipseLink、OpenJPA、Toplink)实现的规范。

您需要选择要使用的提供程序,并将适当的依赖项添加到pom.xml。此外,您还需要在persistence.xml中指定您的提供者。

例如,如果您使用OpenJPA (我在本例中选择它,因为它的最新版本可以在Maven Central Repo中找到,所以不需要配置特定于供应商的存储库):

代码语言:javascript
复制
 <dependencies> 
    <dependency> 
      <groupId>junit</groupId> 
      <artifactId>junit</artifactId> 
      <version>3.8.1</version> 
      <scope>test</scope> 
    </dependency> 
    <!-- Note that you don't need persistence-api dependency - it's transitive -->
    <dependency>
      <groupId>org.apache.openjpa</groupId>
      <artifactId>openjpa-all</artifactId>
      <version>2.0.1</version>
    </dependency>
    <dependency> 
        <groupId>postgresql</groupId> 
        <artifactId>postgresql</artifactId> 
        <version>9.0-801.jdbc4</version> 
    </dependency> 
  </dependencies> 

代码语言:javascript
复制
<persistence xmlns="http://java.sun.com/xml/ns/persistence"       
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"       
        xsi:schemaLocation="http://java.sun.com/xml/ns/persistence       
        http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"       
        version="1.0">       

    <persistence-unit name="EmployeeService" transaction-type="RESOURCE_LOCAL">   
        <!-- Provider specification -->
        <provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider>

        <class>com.mycompany.simpleentity.Employee</class>       
        <properties>       
            <property name="javax.persistence.jdbc.driver"       
                      value="org.postgresql.Driver"/>       
            <property name="javax.persistence.jdbc.url"       
                      value="jdbc:postgresql://localhost:5432/testdb;create=true"/>       
            <property name="javax.persistence.jdbc.user" value="postgres"/>       
            <property name="javax.persistence.jdbc.password" value="111"/>       

        </properties>       
    </persistence-unit>       
</persistence>  
票数 7
EN

Stack Overflow用户

发布于 2012-09-14 21:04:31

如果您使用JPA + eclipselink提供程序,则使用以下代码

代码语言:javascript
复制
<properties>
            <property name="javax.persistence.jdbc.url" value="jdbc:postgresql://localhost/Database name" />
            <property name="javax.persistence.jdbc.user" value="" />
            <property name="javax.persistence.jdbc.password" value="" />
            <property name="javax.persistence.jdbc.driver" value="org.postgresql.Driver" />
</properties>
票数 2
EN

Stack Overflow用户

发布于 2012-12-03 23:20:45

1)确保您已经定义了持久性提供者(对于任何提供者):Ex For openjpa:<persistence-unit ...> <provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider> ... ... </persistence-unit>

2)如果您使用的是自定义构建/编译过程(maven等),请确保将Meta-INF/persistance.xml复制到已编译的/classes文件夹中。

票数 2
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/4261435

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