我在MySQL中有两个表。
CREATE TABLE IF NOT EXISTS `city` (
`city_id` int(11) NOT NULL AUTO_INCREMENT,
`city` varchar(50) NOT NULL,
PRIMARY KEY (`city_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=6 ;
INSERT INTO `city` (`city_id`, `city`) VALUES
(1, 'London'),
(2, 'Moscow'),
(3, 'Perth'),
(4, 'tokyo'),
(5, 'seoul');
CREATE TABLE IF NOT EXISTS `user` (
`user_id` int(11) NOT NULL AUTO_INCREMENT,
`user_name` varchar(20) NOT NULL,
`cities_travel` varchar(50) NOT NULL,
PRIMARY KEY (`user_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;
INSERT INTO `user` (`user_id`, `user_name`, `cities_travel`) VALUES
(1, 'todd', '5'),
(2, 'martin', '1,2,4');我尝试显示如下所示,
1-托德-首尔
2、马丁在伦敦、莫斯科、东京
如何构建查询才能获得高于我们结果的结果?
发布于 2010-11-02 20:27:33
是的,更好的方法是使用feid创建一个单独的表"usercitytrans“。
id (auto increment)
user_id
city_id然后将数据保存在该事务表中。所以你可能有像这样的数据
id user_id city_id
1 1 5
2 1 4
3 1 2
4 2 5
5 1 1在这种情况下,您可以使用下面的sql获得逗号分隔的城市
select u.user_id, user_name,
group_concat(city_name separator ', ' ) as usercities from (user as u left join usercitytrans as ut
on u.user_id = ut.user_id) left join city as c
on ut.city_id = c.city_id
where user_id = 1
group by ut.city_id https://stackoverflow.com/questions/4076962
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