Restlet教程示例

Question

我在让tutorial示例在GAE上工作时遇到了问题。AppEngine日志显示：

"GET /contacts/123 HTTP/1.1" 404 598 - "Restlet-Framework/2.1snapshot,gzip(gfe)"
javax.servlet.ServletContext log: ContactRestlet: [Restlet] Attaching application: com.sem.server.rest.ContactApp@1bbc779 to URI: /contacts/123
This request caused a new process to be started for your application, and thus caused your application code to be loaded for the first time. This request may thus take longer and use more CPU than a typical request for your application.

我无法从android客户端访问它，也无法从浏览器访问它。如有任何帮助，我们不胜感激！

web.xml如下所示

<web-app xmlns="http://java.sun.com/xml/ns/javaee" version="2.5">

<context-param>
    <param-name>org.restlet.clients</param-name>
    <param-value>CLAP FILE</param-value>
  </context-param>  

<servlet>
  <servlet-name>PoiServiceImpl</servlet-name>
  <servlet-class>com.sem.server.PoiServiceImpl</servlet-class>
</servlet>

<servlet>
   <servlet-name>PoiRestlet</servlet-name>
   <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
      <init-param>
        <param-name>org.restlet.application</param-name>
        <param-value>com.sem.server.rest.PoiApp</param-value>
      </init-param>
</servlet>

<servlet>
   <servlet-name>ContactRestlet</servlet-name>
   <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
      <init-param>
        <param-name>org.restlet.application</param-name>
        <param-value>com.sem.server.rest.ContactApp</param-value>
      </init-param>
</servlet>

<servlet>
   <servlet-name>CatRestlet</servlet-name>
   <servlet-class>org.restlet.ext.servlet.ServerServlet</servlet-class>
      <init-param>
        <param-name>org.restlet.application</param-name>
        <param-value>com.sem.server.rest.CatApp</param-value>
      </init-param>
</servlet>

<servlet-mapping>
  <servlet-name>PoiServiceImpl</servlet-name>
  <url-pattern>/sem10/PoiService</url-pattern>
</servlet-mapping>

<servlet-mapping>
    <servlet-name>PoiRestlet</servlet-name>
    <url-pattern>/poi</url-pattern>
</servlet-mapping>

<servlet-mapping>
    <servlet-name>ContactRestlet</servlet-name>
    <url-pattern>/contacts/123</url-pattern>
</servlet-mapping>

<servlet-mapping>
    <servlet-name>CatRestlet</servlet-name>
    <url-pattern>/cat</url-pattern>
</servlet-mapping>


  <!-- Default page to serve -->
  <welcome-file-list>
    <welcome-file>Sem10.html</welcome-file>
  </welcome-file-list>

</web-app>

ContactApp

import java.io.File;    
import org.restlet.Application;
import org.restlet.Component;
import org.restlet.Restlet;
import org.restlet.data.LocalReference;
import org.restlet.data.Protocol;
import org.restlet.resource.Directory;
import org.restlet.routing.Router;

public class ContactApp extends Application {

/**
 * When launched as a standalone application.
 * 
 * @param args
 * @throws Exception
 */
public static void main(String[] args) throws Exception {
    Component component = new Component();
    component.getClients().add(Protocol.FILE);
    component.getServers().add(Protocol.HTTP, 8080);
    component.getDefaultHost().attach(new ContactApp());
    component.start();
}

@Override
public Restlet createInboundRoot() {
    Router router = new Router(getContext());
    getConnectorService().getClientProtocols().add(Protocol.FILE);

 // Serve the files generated by the GWT compilation step.
    File warDir = new File("");
    if (!"war".equals(warDir.getName())) {
        warDir = new File(warDir, "war/");
    }

    Directory dir = new Directory(getContext(), LocalReference
            .createFileReference(warDir));
    router.attachDefault(dir);


       router.attach("/contacts/123", ContactServResource.class);

        return router;
    }
}

Answer 1

Dev-Mailinglist很友好地回答了我的问题：

here