blocks|key|1096554|text|我用我在ASPN上找到的lightweight+XTEA+library解决了这个问题。它不需要任何额外的Python库，并且实现起来相当简单，同时获得了合理的加密级别。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1096555|entityMap|0|LINK|mutability|MUTABLE|url|http://code.activestate.com/recipes/496737/^0|C|O|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

I solved this by using a <a href="http://code.activestate.com/recipes/496737/" rel="nofollow">lightweight XTEA library</a> that i found on ASPN. It doesn't require any additional Python libraries and is quite simple to implement whilst acheiving a resonable encryption level.

blocks|key|3158595|text|看看py-bcrypt吧。也许它能满足你的需要。来自网站：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3158596|Python+bcrypt是OpenBSD密码散列代码的|3158597|包装器，如Niels+Provos和David+Mazières|blockquote|3158598|
的"A+Future-Adaptable+password+Scheme“中所述|3158599|entityMap|0|LINK|mutability|MUTABLE|url|http://www.mindrot.org/projects/py-bcrypt/^0|2|9|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$]]|$1|I|3|J|5|6|7|Y|8|@]|9|@]|C|$]]|$1|K|3|-4|5|6|7|Z|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

Take a look at <a href="http://www.mindrot.org/projects/py-bcrypt/" rel="nofollow">py-bcrypt</a>. Perhaps it will meet your needs. From the web site:

<blockquote>
 py-bcrypt is a Python wrapper of OpenBSD's Blowfish password hashing code, as described in "A Future-Adaptable Password Scheme" by Niels Provos and David Mazières
</blockquote>

blocks|key|1099191|text|KeyCzar有一个很好的界面，应该可以满足你的需求。在主页上：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1099192|1099193|+Keyczar是一个开源加密工具包，旨在使开发人员更容易和更安全地在其应用程序中使用密码学。Keyczar支持使用对称和非对称密钥进行身份验证和加密|blockquote|1099194|1099195|1099196|crypter+=+Crypter.Read("/path/to/your/keys")
ciphertext+=+crypter.Encrypt("Secret+message")|code-block|syntax|javascript|1099197|entityMap|0|LINK|mutability|MUTABLE|url|http://code.google.com/p/keyczar/^0|0|7|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|-4|5|6|7|10|8|@]|9|@]|C|$]]|$1|E|3|F|5|G|7|11|8|@]|9|@]|C|$]]|$1|H|3|-4|5|6|7|12|8|@]|9|@]|C|$]]|$1|I|3|-4|5|6|7|13|8|@]|9|@]|C|$]]|$1|J|3|K|5|L|7|14|8|@]|9|@]|C|$M|N]]|$1|O|3|-4|5|6|7|15|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

<a href="http://code.google.com/p/keyczar/" rel="nofollow">KeyCzar</a> has a nice interface and should meet your requirements. From the home page:

<blockquote>
 Keyczar is an open source cryptographic toolkit designed to make it easier and safer for devlopers to use cryptography in their applications. Keyczar supports authentication and encryption with both symmetric and asymmetric keys
</blockquote>

<pre><code>crypter = Crypter.Read("/path/to/your/keys")
ciphertext = crypter.Encrypt("Secret message")
</code></pre>

blocks|key|4569409|text|我最近创建了一段代码，它几乎实现了您所说的内容。它采用诸如'abc‘这样的码字来获取值(1，2，3)，然后将它们添加到要加密的单词中的每个字母上。因此，如果’abc‘是码字，'bcd’是要加密的文本。(1%2B2+=3，2%2B3+=5，3%2B4+=+7)，因此输出应该是'ceg‘。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4569410|codeword+=+input('Enter+codeword+:+')
codeword+=+codeword.replace("+",+"")++

encrypt+=+input('Enter+text+to+encrypt+:+')
encrypt+=+encrypt.replace("+",+"")

j+=+0
for+i+in+codeword:
++++print(chr(ord(encrypt[j])%2B+ord(codeword[j])-96))
++++j%2B=1|code-block|syntax|javascript|4569411|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I recently created a piece of code that does pretty much what your saying. It takes a codeword such as 'abc'gets the values (1, 2, 3) and then adds them to each letter in the word to encrypt. So if 'abc' was the codeword and 'bcd' the text to encrypt. (1+2 =3 2+3 =5 and 3+4 = 7) so the output would then be 'ceg'

<pre><code>codeword = input('Enter codeword : ')
codeword = codeword.replace(" ", "") 

encrypt = input('Enter text to encrypt : ')
encrypt = encrypt.replace(" ", "")

j = 0
for i in codeword:
 print(chr(ord(encrypt[j])+ ord(codeword[j])-96))
 j+=1
</code></pre>

blocks|key|1099241|text|下面是我的代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1099242|from+cryptography.fernet+import+Fernet
import+pyperclip

print("For+this+program+to+work,+please+send+the+file+named+'pwkey'+and+the+encrypted+code+to+the+other+user.")
key+=+Fernet.generate_key()
file+=+open('pwkey',+'wb')
file.write(key)
file.close()
print('File+Generated')
original+=+input('Enter+message>>>')
message+=+original.encode()
f+=+Fernet(key)
encrypted+=+f.encrypt(message)
encrypted+=+encrypted.decode("ascii")
print('Encrypted:',+encrypted)
pyperclip.copy(encrypted)
print('Please+tell+the+other+user+to+input+the+encrypted+code+in+the+Decrypt+program')
print('(Code+copied+to+Clipboard)')
print("Note:+Please+delete+the+'pwkey'+file+after+sending+it+to+the+other+user.+It+
++++is+for+one-time+use+only.")|code-block|syntax|javascript|1099243|和解密|1099244|#+Decrypt
from+cryptography.fernet+import+Fernet

print("For+this+program+to+work,+make+sure+you+have+the+file+named+'pwkey'+in+your+Python+folder+and+the+encrypted+"
++++++++"code.")
file+=+open('pwkey',+'rb')
key+=+file.read()
file.close()
print('Key+Retrieved')
encrypted+=+input('Please+input+your+encrypted+code>>>')
encrypted+=+bytes(encrypted,+'utf-8')
f+=+Fernet(key)
decrypted+=+f.decrypt(encrypted)
decrypted+=+decrypted.decode()
print('Decrypted+Message:')
print(decrypted)
print("Note:+Please+delete+the+'pwkey'+file+after+getting+the+decrypted+message.+It+is+for+one-time+use+only.")|1099245|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Here's my code:

<pre><code>from cryptography.fernet import Fernet
import pyperclip

print("For this program to work, please send the file named 'pwkey' and the encrypted code to the other user.")
key = Fernet.generate_key()
file = open('pwkey', 'wb')
file.write(key)
file.close()
print('File Generated')
original = input('Enter message&gt;&gt;&gt;')
message = original.encode()
f = Fernet(key)
encrypted = f.encrypt(message)
encrypted = encrypted.decode("ascii")
print('Encrypted:', encrypted)
pyperclip.copy(encrypted)
print('Please tell the other user to input the encrypted code in the Decrypt program')
print('(Code copied to Clipboard)')
print("Note: Please delete the 'pwkey' file after sending it to the other user. It 
 is for one-time use only.")
</code></pre>

And decrypting

<pre><code># Decrypt
from cryptography.fernet import Fernet

print("For this program to work, make sure you have the file named 'pwkey' in your Python folder and the encrypted "
 "code.")
file = open('pwkey', 'rb')
key = file.read()
file.close()
print('Key Retrieved')
encrypted = input('Please input your encrypted code&gt;&gt;&gt;')
encrypted = bytes(encrypted, 'utf-8')
f = Fernet(key)
decrypted = f.decrypt(encrypted)
decrypted = decrypted.decode()
print('Decrypted Message:')
print(decrypted)
print("Note: Please delete the 'pwkey' file after getting the decrypted message. It is for one-time use only.")
</code></pre>

blocks|key|1099331|text|我会使用易于使用的cryptocode库(https://github.com/gdavid7/cryptocode)来做到这一点。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1099332|与其他库相比，加密和解密相对简单：|1099333|##+Encrypting:
>>>+import+cryptocode
>>>+myEncryptedMessage+=+cryptocode.encrypt("I+like+trains",+"password123")
>>>+print(myEncryptedMessage)
M%2BWykmlub0z7FhEdmA==*PvAbXRNx0SiSDHHxLsKZ5w==*ihQM/fdkgrX3G%2ByOItyAUQ==*QFNDmuUP1ysgo01/P2MNpg==

##+Decrypting:
>>>+import+cryptocode
>>>+myDecryptedMessage+=+cryptocode.decrypt("M%2BWykmlub0z7FhEdmA==*PvAbXRNx0SiSDHHxLsKZ5w==*ihQM/fdkgrX3G%2ByOItyAUQ==*QFNDmuUP1ysgo01/P2MNpg==",+"password123")
>>>+print(myDecryptedMessage)
I+like+trains|code-block|syntax|javascript|1099334|与其他库相比，这个库的唯一一个重大缺点是，与其他加密库相比，它没有太多的选项可以在字符串周围进行更改。但它对于很多人来说是完美的，他们只想要一个抽象，而不需要配置自定义设置。|1099335|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/gdavid7/cryptocode^0|9|A|L|11|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|6|7|12|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|13|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|14|8|@]|D|@]|E|$]]|$1|O|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

I would do this with the easy to use <code>cryptocode</code> library (<a href="https://github.com/gdavid7/cryptocode" rel="nofollow noreferrer">https://github.com/gdavid7/cryptocode</a>).
Encrypting and decrypting is relatively simple compared to other libraries:
<pre><code>## Encrypting:
&gt;&gt;&gt; import cryptocode
&gt;&gt;&gt; myEncryptedMessage = cryptocode.encrypt(&quot;I like trains&quot;, &quot;password123&quot;)
&gt;&gt;&gt; print(myEncryptedMessage)
M+Wykmlub0z7FhEdmA==*PvAbXRNx0SiSDHHxLsKZ5w==*ihQM/fdkgrX3G+yOItyAUQ==*QFNDmuUP1ysgo01/P2MNpg==

## Decrypting:
&gt;&gt;&gt; import cryptocode
&gt;&gt;&gt; myDecryptedMessage = cryptocode.decrypt(&quot;M+Wykmlub0z7FhEdmA==*PvAbXRNx0SiSDHHxLsKZ5w==*ihQM/fdkgrX3G+yOItyAUQ==*QFNDmuUP1ysgo01/P2MNpg==&quot;, &quot;password123&quot;)
&gt;&gt;&gt; print(myDecryptedMessage)
I like trains
</code></pre>
The only large disadvantage to this library over others is that it does not have many options to change around your string compared to other cryptography libraries. But it is perfect for a lot of people who just want an abstraction, and don't need to configure custom settings.

I need to encrypt a small string in Python. Is it possible to use a secret key to encrypt the string? Is there a good way to do this and achieve a reasonable encryption level using only Python libraries? Could you show me how to do this?

My knowledge about cryptography is quite basic.

Encrypt string in Python

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我需要用Python加密一个小字符串。可以使用密钥对字符串进行加密吗？有没有一种很好的方法来做到这一点，并且只使用Python库就能达到合理的加密级别？你能教我怎么做吗？我的密码学知识非常基础。

问在Python中加密字符串
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回答 6

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