我在创建特定的数组时遇到了麻烦。我想要的是为我的成员拉取信息(从mysql数据库),然后将它们存储到一个数组中。数组应如下所示:
$members = array(
'John' => array('avatar' => '/images/avatar/ji.jpg', 'country' => 'uk.'),
'Nick' => array('avatar' => '/images/avatar/nick.jpg', 'country' => 'italy.'),
);等等。因此,我从数据库中提取名称、头像url和国家,然后将它们存储到前一个数组中。我的问题是,如何创建此数组?
提前感谢!
关于在php中创建数组。
发布于 2010-09-06 04:35:58
像这样的东西应该是有效的:
$members = array();
$q = mysql_query("SELECT name , avatar, country from table");
while($row = mysql_fetch_assoc($q)){
$array = array("avatar" => $row['avatar'] , "country" => $row['country']);
$members[$row['name']] = $array;
}发布于 2010-09-06 04:38:27
使用PDO:
$members = array();
$conn = new PDO("mysql:host=$host;dbname=$database", $username, $password);
$sql = "SELECT name, avatar, country FROM members";
foreach ($conn->query($sql) as $row) {
$temp = array('avatar' => $row['avatar'], 'country' => $row['country']);
$members[$row['name']] = $temp;
}https://stackoverflow.com/questions/3647689
复制相似问题