我想问是否有人可以帮助他让这段代码正常工作。我的MySQL数据库中什么也没有显示。谢谢,恩布尔。
NSString *urlstr = [[NSString alloc] initWithFormat:@"http://mysite.come/myapp/submitrating.php?name=%@&comment=%@&rating=%@",
[selectedItem objectForKey:@"name"], comment.text, selectedRating];
NSString *urlstrEncoded = [urlstr stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [[NSURL alloc] initWithString:urlstrEncoded];
[urlstr release];
[url release];发布于 2010-09-06 10:50:28
我让它和这段代码一起工作。
NSString *urlstr = [NSString stringWithFormat:@"http://mysite.com/myapp/submitrating.php?name=%@&comment=%@&rating=%@", [selectedItem objectForKey:@"name"], comment.text, selectedRating];
NSString *urlEncoded = [urlstr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [[NSURL alloc] initWithString:urlEncoded];
NSString *ans = [NSString stringWithContentsOfURL:url encoding:NSASCIIStringEncoding error:nil];发布于 2010-08-28 07:34:59
你需要做的远不止这些!您至少需要以下内容:
NSMutableURLRequest *theRequest = [NSMutableURLRequest requestWithURL:theURL cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:10.0];
NSURLConnection *theConnection = [[NSURLConnection alloc] initWithRequest:theRequest delegate:self];同时实现以下方法:
-(void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error
-(void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response发布于 2010-08-28 07:32:53
除了创建URL对象之外,您没有对它执行任何操作。也许你想尝试一下NSURLConnection
https://stackoverflow.com/questions/3588753
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