我正在尝试做以下几件事:
$string = "<object width=\"425\" height=\"350\">
<param name=\"movie\" value=\"http://www.youtube.com/v/1OtdDqF5rnI&autoplay=0\"></param>
<param name=\"wmode\" value=\"transparent\"></param>
<embed src=\"http://www.youtube.com/v/1OtdDqF5rnI&autoplay=0\" type=\"application/x-shockwave-flash\" wmode=\"transparent\" width=\"425\" height=\"350\"></embed>
</object>";
$doc = new DOMDocument();
$doc->loadXML($string);当我加载字符串时,我得到以下错误:
[phpBB Debug] PHP Notice: in file /mnt/FS-2/Critical/Media/Private/Website/Online/blitz1up.com/application/controllers/articles.php on line 303: DOMDocument::loadXML() [domdocument.loadxml]: EntityRef: expecting ';' in Entity, line: 2
[phpBB Debug] PHP Notice: in file /mnt/FS-2/Critical/Media/Private/Website/Online/blitz1up.com/application/controllers/articles.php on line 303: DOMDocument::loadXML() [domdocument.loadxml]: EntityRef: expecting ';' in Entity, line: 4我已经将原因缩小到YouTube URL,但不确定解决此错误的最佳方法。因此,任何建议都是非常受欢迎的。
发布于 2010-08-18 17:29:41
URL包含&符号,当不用于声明实体时,应将其编码为&。解析器假设&autoload将开始一个新的实体,但它永远不会以分号结束。
要使用超文本标记语言,请考虑使用loadHTML();加载片段,并禁用该部分的错误:
libxml_use_internal_errors(TRUE);
$doc = new DOMDocument();
$doc->loadHTML($string);
libxml_clear_errors();
echo $doc->saveHTML();上面的方法也适用于loadXML。
https://stackoverflow.com/questions/3510574
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