为什么这种复数类别名称的方法并不在所有情况下都有效？

Question

PLURALIZATION_EXCEPTIONS = "hardware",'memory'
def pluralize_category_name(name)
  category = name.split(' and ')
  exceptions_to_exp = ""

  category.map! { |e| 
    if e.match(/^[A-Z]+$/)  and !e.match(/^[A-Z]+S$/)
      e = e.pluralize
    end
    (PLURALIZATION_EXCEPTIONS.include?(e.downcase)  || e.match(/^[A-Z]+S$/) ||
      e.match(/[memory|hardware]/) )? e : e.pluralize
  }.join(' and ')
end

测试应该和期望应该如下所示：

it "properly pluralizes hardware as hardware" do
   pluralize_category_name("hardware").should == "hardware"
end

it "properly pluralizes UPS as UPS" do
   pluralize_category_name("UPS").should == "UPS"
end

it "properly pluralizes PDA and Portable Hardware as PDAs and Portable Hardware" do
   pluralize_category_name("PDA and Portable Hardware").should == "PDAs and Portable Hardware"
end

it "properly pluralizes perfume and cologne as perfumes and colognes" do
   pluralize_category_name("perfume and cologne").should == "perfumes and colognes"
end

最后一次测试失败:(

帮助!

Answer 1

我想你的问题是以你的情况

(PLURALIZATION_EXCEPTIONS.include?(e.downcase)  || e.match(/^[A-Z]+S$/) ||
      e.match(/[memory|hardware]/) )? e : e.pluralize

"perfume"与/[memory|hardware]/匹配。

[memory|hardware]是与m、e、m、o、r等中的任何一个匹配的character class。

也许你指的是e.match(/(memory|hardware)]/i)？这个替代模式可以通过您的测试，但是它不使用您的PLURALIZATION_EXCEPTIONS常量，因此如果您添加了任何其他异常，则需要进行更新。