blocks|key|2741501|text|您确实有一个RTRIM和一个LTRIM函数。您可以将它们组合在一起，以获得所需的trim函数。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2741502|UPDATE+Table
SET+Name+=+RTRIM(LTRIM(Name))|code-block|syntax|javascript|2741503|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/ms178660.aspx|1|http://msdn.microsoft.com/en-us/library/ms177827.aspx^0|6|5|E|5|6|5|0|E|5|1|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]|$9|12|A|13|1|14]]|E|$]]|$1|F|3|G|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]|S|$5|N|O|P|E|$Q|T]]]]

You do have an <a href="http://msdn.microsoft.com/en-us/library/ms178660.aspx" rel="noreferrer"><code>RTRIM</code></a> and an <a href="http://msdn.microsoft.com/en-us/library/ms177827.aspx" rel="noreferrer"><code>LTRIM</code></a> function. You can combine them to get the trim function you want.

<pre><code>UPDATE Table
SET Name = RTRIM(LTRIM(Name))
</code></pre>

blocks|key|2741552|text|您可以使用RTrim函数从右侧修剪所有空格。使用LTrim从左侧修剪所有空格。例如|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2741553|UPDATE+Table+SET+Name+=+RTrim(Name)|code-block|syntax|javascript|2741554|或者同时用于左右修剪|2741555|UPDATE+Table+SET+Name+=+LTrim(RTrim(Name))|2741556|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can use the RTrim function to trim all whitespace from the right. Use LTrim to trim all whitespace from the left. For example

<pre><code>UPDATE Table SET Name = RTrim(Name)
</code></pre>

Or for both left and right trim

<pre><code>UPDATE Table SET Name = LTrim(RTrim(Name))
</code></pre>

blocks|key|889577|text|SQL+Server没有TRIM函数，而是有两个。一个用于专门修剪字符串“前面”的空格(LTRIM)，另一个用于修剪字符串“末端”的空格(RTRIM)。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|889578|下面的代码将更新表中的每条记录，修剪varchar/nvarchar字段的所有无关空格(前面或结尾)：|889579|UPDATE+
+++[YourTableName]
SET
+++[YourFieldName]+=+LTRIM(RTRIM([YourFieldName]))|code-block|syntax|javascript|889580|(奇怪的是，SSIS+(Sql+Server+Integration+Services)确实只有一个TRIM函数！)|889581|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/ms177827.aspx|1|http://msdn.microsoft.com/en-us/library/ms178660.aspx|2|http://msdn.microsoft.com/en-us/library/ms139947.aspx^0|18|5|0|1X|5|1|0|0|0|1E|4|2|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]|$A|12|B|13|1|14]]|C|$]]|$1|D|3|E|5|6|7|15|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|16|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|17|8|@]|9|@$A|18|B|19|1|1A]]|C|$]]|$1|M|3|-4|5|6|7|1B|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]|U|$5|P|Q|R|C|$S|V]]|W|$5|P|Q|R|C|$S|X]]]]

SQL Server does not have a TRIM function, but rather it has two. One each for specifically trimming spaces from the "front" of a string (<a href="http://msdn.microsoft.com/en-us/library/ms177827.aspx" rel="nofollow noreferrer">LTRIM</a>) and one for trimming spaces from the "end" of a string (<a href="http://msdn.microsoft.com/en-us/library/ms178660.aspx" rel="nofollow noreferrer">RTRIM</a>).

Something like the following will update every record in your table, trimming all extraneous space (either at the front or the end) of a varchar/nvarchar field:

<pre><code>UPDATE 
 [YourTableName]
SET
 [YourFieldName] = LTRIM(RTRIM([YourFieldName]))
</code></pre>

(Strangely, SSIS (Sql Server Integration Services) does have a single <a href="http://msdn.microsoft.com/en-us/library/ms139947.aspx" rel="nofollow noreferrer">TRIM</a> function!)

blocks|key|887597|text|我会尝试这样的Trim函数，它考虑到Unicode标准定义的所有空格字符(LTRIM和RTRIM甚至不修剪换行符！)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|887598|​|887599|IF+OBJECT_ID(N'dbo.IsWhiteSpace',+N'FN')+IS+NOT+NULL
++++DROP+FUNCTION+dbo.IsWhiteSpace;
GO

--+Determines+whether+a+single+character+is+white-space+or+not+(according+to+the+UNICODE+standard).
CREATE+FUNCTION+dbo.IsWhiteSpace(@c+NCHAR(1))+RETURNS+BIT
BEGIN
	IF+(@c+IS+NULL)+RETURN+NULL;
	DECLARE+@WHITESPACE+NCHAR(31);
	SELECT+@WHITESPACE+=+'+'+%2B+NCHAR(13)+%2B+NCHAR(10)+%2B+NCHAR(9)+%2B+NCHAR(11)+%2B+NCHAR(12)+%2B+NCHAR(133)+%2B+NCHAR(160)+%2B+NCHAR(5760)+%2B+NCHAR(8192)+%2B+NCHAR(8193)+%2B+NCHAR(8194)+%2B+NCHAR(8195)+%2B+NCHAR(8196)+%2B+NCHAR(8197)+%2B+NCHAR(8198)+%2B+NCHAR(8199)+%2B+NCHAR(8200)+%2B+NCHAR(8201)+%2B+NCHAR(8202)+%2B+NCHAR(8232)+%2B+NCHAR(8233)+%2B+NCHAR(8239)+%2B+NCHAR(8287)+%2B+NCHAR(12288)+%2B+NCHAR(6158)+%2B+NCHAR(8203)+%2B+NCHAR(8204)+%2B+NCHAR(8205)+%2B+NCHAR(8288)+%2B+NCHAR(65279);
	IF+(CHARINDEX(@c,+@WHITESPACE)+=+0)+RETURN+0;
	RETURN+1;
END
GO

IF+OBJECT_ID(N'dbo.Trim',+N'FN')+IS+NOT+NULL
++++DROP+FUNCTION+dbo.Trim;
GO

--+Removes+all+leading+and+tailing+white-space+characters.+NULL+is+converted+to+an+empty+string.
CREATE+FUNCTION+dbo.Trim(@TEXT+NVARCHAR(MAX))+RETURNS+NVARCHAR(MAX)
BEGIN
	--+Check+tiny+strings+(NULL,+0+or+1+chars)
	IF+@TEXT+IS+NULL+RETURN+N'';
	DECLARE+@TEXTLENGTH+INT+=+LEN(@TEXT);
	IF+@TEXTLENGTH+<+2+BEGIN
		IF+(@TEXTLENGTH+=+0)+RETURN+@TEXT;
		IF+(dbo.IsWhiteSpace(SUBSTRING(@TEXT,+1,+1))+=+1)+RETURN+'';
		RETURN+@TEXT;
	END
	--+Check+whether+we+have+to+LTRIM/RTRIM
	DECLARE+@SKIPSTART+INT;
	SELECT+@SKIPSTART+=+dbo.IsWhiteSpace(SUBSTRING(@TEXT,+1,+1));
	DECLARE+@SKIPEND+INT;
	SELECT+@SKIPEND+=+dbo.IsWhiteSpace(SUBSTRING(@TEXT,+@TEXTLENGTH,+1));
	DECLARE+@INDEX+INT;
	IF+(@SKIPSTART+=+1)+BEGIN
		IF+(@SKIPEND+=+1)+BEGIN
			--+FULLTRIM
			--+Determine+start+white-space+length
			SELECT+@INDEX+=+2;
			WHILE+(@INDEX+<+@TEXTLENGTH)+BEGIN+--+Hint:+The+last+character+is+already+checked
				--+Stop+loop+if+no+white-space
				IF+(dbo.IsWhiteSpace(SUBSTRING(@TEXT,+@INDEX,+1))+=+0)+BREAK;
				--+Otherwise+assign+index+as+@SKIPSTART
				SELECT+@SKIPSTART+=+@INDEX;
				--+Increase+character+index
				SELECT+@INDEX+=+(@INDEX+%2B+1);
			END
			--+Return+''+if+the+whole+string+is+white-space
			IF+(@SKIPSTART+=+(@TEXTLENGTH+-+1))+RETURN+'';+
			--+Determine+end+white-space+length
			SELECT+@INDEX+=+(@TEXTLENGTH+-+1);
			WHILE+(@INDEX+>+1)+BEGIN+
				--+Stop+loop+if+no+white-space
				IF+(dbo.IsWhiteSpace(SUBSTRING(@TEXT,+@INDEX,+1))+=+0)+BREAK;
				--+Otherwise+increase+@SKIPEND
				SELECT+@SKIPEND+=+(@SKIPEND+%2B+1);
				--+Decrease+character+index
				SELECT+@INDEX+=+(@INDEX+-+1);
			END
			--+Return+trimmed+string
			RETURN+SUBSTRING(@TEXT,+@SKIPSTART+%2B+1,+@TEXTLENGTH+-+@SKIPSTART+-+@SKIPEND);
		END+
		--+LTRIM
		--+Determine+start+white-space+length
		SELECT+@INDEX+=+2;
		WHILE+(@INDEX+<+@TEXTLENGTH)+BEGIN+--+Hint:+The+last+character+is+already+checked
			--+Stop+loop+if+no+white-space
			IF+(dbo.IsWhiteSpace(SUBSTRING(@TEXT,+@INDEX,+1))+=+0)+BREAK;
			--+Otherwise+assign+index+as+@SKIPSTART
			SELECT+@SKIPSTART+=+@INDEX;
			--+Increase+character+index
			SELECT+@INDEX+=+(@INDEX+%2B+1);
		END
		--+Return+trimmed+string
		RETURN+SUBSTRING(@TEXT,+@SKIPSTART+%2B+1,+@TEXTLENGTH+-+@SKIPSTART);
	END+ELSE+BEGIN
		--+RTRIM
		IF+(@SKIPEND+=+1)+BEGIN
			--+Determine+end+white-space+length
			SELECT+@INDEX+=+(@TEXTLENGTH+-+1);
			WHILE+(@INDEX+>+1)+BEGIN+
				--+Stop+loop+if+no+white-space
				IF+(dbo.IsWhiteSpace(SUBSTRING(@TEXT,+@INDEX,+1))+=+0)+BREAK;
				--+Otherwise+increase+@SKIPEND
				SELECT+@SKIPEND+=+(@SKIPEND+%2B+1);
				--+Decrease+character+index
				SELECT+@INDEX+=+(@INDEX+-+1);
			END
			--+Return+trimmed+string
			RETURN+SUBSTRING(@TEXT,+1,+@TEXTLENGTH+-+@SKIPEND);
		END+
	END
	--+NO+TRIM
	RETURN+@TEXT;
END
GO|code-block|syntax|javascript|887600|887601|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

I would try something like this for a Trim function that takes into account all white-space characters defined by the Unicode Standard (LTRIM and RTRIM do not even trim new-line characters!):

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-html lang-html prettyprint-override"><code>IF OBJECT_ID(N'dbo.IsWhiteSpace', N'FN') IS NOT NULL
 DROP FUNCTION dbo.IsWhiteSpace;
GO

-- Determines whether a single character is white-space or not (according to the UNICODE standard).
CREATE FUNCTION dbo.IsWhiteSpace(@c NCHAR(1)) RETURNS BIT
BEGIN
	IF (@c IS NULL) RETURN NULL;
	DECLARE @WHITESPACE NCHAR(31);
	SELECT @WHITESPACE = ' ' + NCHAR(13) + NCHAR(10) + NCHAR(9) + NCHAR(11) + NCHAR(12) + NCHAR(133) + NCHAR(160) + NCHAR(5760) + NCHAR(8192) + NCHAR(8193) + NCHAR(8194) + NCHAR(8195) + NCHAR(8196) + NCHAR(8197) + NCHAR(8198) + NCHAR(8199) + NCHAR(8200) + NCHAR(8201) + NCHAR(8202) + NCHAR(8232) + NCHAR(8233) + NCHAR(8239) + NCHAR(8287) + NCHAR(12288) + NCHAR(6158) + NCHAR(8203) + NCHAR(8204) + NCHAR(8205) + NCHAR(8288) + NCHAR(65279);
	IF (CHARINDEX(@c, @WHITESPACE) = 0) RETURN 0;
	RETURN 1;
END
GO

IF OBJECT_ID(N'dbo.Trim', N'FN') IS NOT NULL
 DROP FUNCTION dbo.Trim;
GO

-- Removes all leading and tailing white-space characters. NULL is converted to an empty string.
CREATE FUNCTION dbo.Trim(@TEXT NVARCHAR(MAX)) RETURNS NVARCHAR(MAX)
BEGIN
	-- Check tiny strings (NULL, 0 or 1 chars)
	IF @TEXT IS NULL RETURN N'';
	DECLARE @TEXTLENGTH INT = LEN(@TEXT);
	IF @TEXTLENGTH &lt; 2 BEGIN
		IF (@TEXTLENGTH = 0) RETURN @TEXT;
		IF (dbo.IsWhiteSpace(SUBSTRING(@TEXT, 1, 1)) = 1) RETURN '';
		RETURN @TEXT;
	END
	-- Check whether we have to LTRIM/RTRIM
	DECLARE @SKIPSTART INT;
	SELECT @SKIPSTART = dbo.IsWhiteSpace(SUBSTRING(@TEXT, 1, 1));
	DECLARE @SKIPEND INT;
	SELECT @SKIPEND = dbo.IsWhiteSpace(SUBSTRING(@TEXT, @TEXTLENGTH, 1));
	DECLARE @INDEX INT;
	IF (@SKIPSTART = 1) BEGIN
		IF (@SKIPEND = 1) BEGIN
			-- FULLTRIM
			-- Determine start white-space length
			SELECT @INDEX = 2;
			WHILE (@INDEX &lt; @TEXTLENGTH) BEGIN -- Hint: The last character is already checked
				-- Stop loop if no white-space
				IF (dbo.IsWhiteSpace(SUBSTRING(@TEXT, @INDEX, 1)) = 0) BREAK;
				-- Otherwise assign index as @SKIPSTART
				SELECT @SKIPSTART = @INDEX;
				-- Increase character index
				SELECT @INDEX = (@INDEX + 1);
			END
			-- Return '' if the whole string is white-space
			IF (@SKIPSTART = (@TEXTLENGTH - 1)) RETURN ''; 
			-- Determine end white-space length
			SELECT @INDEX = (@TEXTLENGTH - 1);
			WHILE (@INDEX &gt; 1) BEGIN 
				-- Stop loop if no white-space
				IF (dbo.IsWhiteSpace(SUBSTRING(@TEXT, @INDEX, 1)) = 0) BREAK;
				-- Otherwise increase @SKIPEND
				SELECT @SKIPEND = (@SKIPEND + 1);
				-- Decrease character index
				SELECT @INDEX = (@INDEX - 1);
			END
			-- Return trimmed string
			RETURN SUBSTRING(@TEXT, @SKIPSTART + 1, @TEXTLENGTH - @SKIPSTART - @SKIPEND);
		END 
		-- LTRIM
		-- Determine start white-space length
		SELECT @INDEX = 2;
		WHILE (@INDEX &lt; @TEXTLENGTH) BEGIN -- Hint: The last character is already checked
			-- Stop loop if no white-space
			IF (dbo.IsWhiteSpace(SUBSTRING(@TEXT, @INDEX, 1)) = 0) BREAK;
			-- Otherwise assign index as @SKIPSTART
			SELECT @SKIPSTART = @INDEX;
			-- Increase character index
			SELECT @INDEX = (@INDEX + 1);
		END
		-- Return trimmed string
		RETURN SUBSTRING(@TEXT, @SKIPSTART + 1, @TEXTLENGTH - @SKIPSTART);
	END ELSE BEGIN
		-- RTRIM
		IF (@SKIPEND = 1) BEGIN
			-- Determine end white-space length
			SELECT @INDEX = (@TEXTLENGTH - 1);
			WHILE (@INDEX &gt; 1) BEGIN 
				-- Stop loop if no white-space
				IF (dbo.IsWhiteSpace(SUBSTRING(@TEXT, @INDEX, 1)) = 0) BREAK;
				-- Otherwise increase @SKIPEND
				SELECT @SKIPEND = (@SKIPEND + 1);
				-- Decrease character index
				SELECT @INDEX = (@INDEX - 1);
			END
			-- Return trimmed string
			RETURN SUBSTRING(@TEXT, 1, @TEXTLENGTH - @SKIPEND);
		END 
	END
	-- NO TRIM
	RETURN @TEXT;
END
GO</code></pre>
</div>
</div>

blocks|key|1632413|text|我知道这是一个古老的问题，但我刚刚找到了一个解决方案，它使用LTRIM和RTRIM创建用户定义的函数。它不处理字符串中间的双空格。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1632414|然而，解决方案是直接的：|1632415|User+Defined+Trim+Function|offset|length|1632416|entityMap|0|LINK|mutability|MUTABLE|url|http://blog.sqlauthority.com/2008/10/09/sql-server-2008-trim-function-user-defined-function/^0|0|0|0|Q|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@$F|S|G|T|1|U]]|A|$]]|$1|H|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|O]]]]

I know this is an old question but I just found a solution which creates a user defined function using LTRIM and RTRIM. It does not handle double spaces in the middle of a string. 

The solution is however straight forward:

<a href="http://blog.sqlauthority.com/2008/10/09/sql-server-2008-trim-function-user-defined-function/" rel="nofollow">User Defined Trim Function</a>

blocks|key|1636269|text|没有答案是真的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1636270|正确答案是Edit+Column+to+NVARCHAR，您发现了Automatically+trim+Execute，但此代码更新Table+SET+Name+=+RTRIM(LTRIM(Name))仅与Nvarchar一起使用如果与CHAR或NCHAR一起使用则不起作用|1636271|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

No Answer is true 

The true Answer is Edit Column to NVARCHAR and you found Automatically trim Execute but this code 
UPDATE Table
SET Name = RTRIM(LTRIM(Name))
use it only with Nvarchar if use it with CHAR or NCHAR it will not work

blocks|key|4149888|text|此函数用于从左向右修剪字符串。此外，它还删除字符串中的回车，这是LTRIM和RTRIM不能完成的操作|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4149889|IF+OBJECT_ID(N'dbo.TRIM',+N'FN')+IS+NOT+NULL
++++DROP+FUNCTION+dbo.TRIM;
GO
CREATE+FUNCTION+dbo.TRIM+(@STR+NVARCHAR(MAX))+RETURNS+NVARCHAR(MAX)
BEGIN
++++RETURN(LTRIM(RTRIM(REPLACE(REPLACE(@STR+,CHAR(10),''),CHAR(13),''))))
END;
GO|code-block|syntax|javascript|4149890|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This function trims a string from left and right. Also it removes carriage returns from the string, an action which is not done by the LTRIM and RTRIM

<pre><code>IF OBJECT_ID(N'dbo.TRIM', N'FN') IS NOT NULL
 DROP FUNCTION dbo.TRIM;
GO
CREATE FUNCTION dbo.TRIM (@STR NVARCHAR(MAX)) RETURNS NVARCHAR(MAX)
BEGIN
 RETURN(LTRIM(RTRIM(REPLACE(REPLACE(@STR ,CHAR(10),''),CHAR(13),''))))
END;
GO
</code></pre>

I have a table in a SQL Server 2008 database. This table has a nvarchar(256) column called 'Name'. Unfortunately, the values in this field have extra spaces included. For instance the name 'Bill' is actually stored as 'Bill ' in the table. 

I want to update all of the records in this table to remove the extra spaces. However, I was surprised to learn that SQL does not have a TRIM function. 

How do I update all of the records at once to remove the extra spaces?

Thank you!

Trimming text strings in SQL Server 2008

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我在SQL Server 2008数据库中有一个表。该表有一个名为'Name‘的nvarchar(256)列。遗憾的是，此字段中的值包含额外的空格。例如，名字'Bill‘实际上在表中存储为'Bill’。我想要更新这个表中的所有记录，以删除多余的空格。然而，我很惊讶地发现SQL没有TRIM函数。如何一次更新所有记录以删除多余的空格？谢谢!

问在SQL Server 2008中裁切文本字符串
EN

回答 7

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