我有一张桌子
CREATE TABLE `zipcodes2` (
`ID` int(11) NOT NULL auto_increment,
`zipcode` int(6) NOT NULL default '0',
`State` char(3) NOT NULL default '',
`zip_name` varchar(255) NOT NULL default '',
`CityAliasName` varchar(255) NOT NULL default '',
`latitude` float(26,7) NOT NULL default '0.0000000',
`longitude` float(36,7) NOT NULL default '0.0000000',
`AreaCode` smallint(3) NOT NULL default '0',
`County` varchar(255) NOT NULL default '',
`TimeZone` smallint(3) NOT NULL default '0',
`DayLightSavings` char(2) NOT NULL default '',
PRIMARY KEY (`zipcode`,`CityAliasName`,`ID`),
KEY `CityAliasName` (`CityAliasName`),
KEY `State` (`State`),
KEY `index_by_zipcode` (`zipcode`),
KEY `index_by_state` (`State`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;我正在尝试从另一个表插入到这个表中。问题是auto_increment字段没有递增。我做错了什么?
insert into zipcodes2 (ID,zipcode,state,zip_name,CityAliasName,latitude,longitude, AreaCode, County, TimeZone, DayLightSavings)
select distinct null,ZipCode as zipcode,State as state,City as zip_name, CityAliasName, Latitude as latitude, Longitude as longitude, AreaCode
, County, TimeZone, DayLightSavings
from zip_codes_all
where state NOT in ('PR', 'AE', 'PW', 'MP', 'GU', 'FM', 'AS','AP', 'AA','FM','GA','GU','FM')
limit 0,10;发布于 2010-08-02 13:30:49
问题是,
主键(zipcode、CityAliasName、ID)
应该是这样的,
主键(ID)
一旦我改变了这一点,并从插入中删除了ID字段,我就得到了我所期望的结果。
发布于 2010-08-02 13:15:43
请尝试从查询中删除“ID”:
insert into zipcodes2 (zipcode,state,zip_name,CityAliasName,latitude,longitude, AreaCode, County, TimeZone, DayLightSavings)
select distinct ZipCode as zipcode,State as state,City as zip_name, CityAliasName, Latitude as latitude, Longitude as longitude, AreaCode, County, TimeZone, DayLightSavings
from zip_codes_all
where state NOT in ('PR', 'AE', 'PW', 'MP', 'GU', 'FM', 'AS','AP', 'AA','FM','GA','GU','FM')
limit 0,10;发布于 2010-08-02 13:49:24
是的,主键定义是一个键。正如mysql文档所说:
对于MyISAM和BDB表,您可以在多列索引中的辅助列上指定AUTO_INCREMENT。在本例中,为前缀列生成的值的计算公式为MAX(auto_increment_column) +1,其中AUTO_INCREMENT =给定前缀。当您想要将数据放入有序组中时,这很有用。
可能在修复主键之前,你的id得到了不唯一的值。
https://stackoverflow.com/questions/3385160
复制相似问题