我想从SQL server中的查询中返回10个最常用的单词,所以在一组行上运行,如下所示:
敏捷的棕色狐狸
慢黄狐
慢绿狐
将会返回
狐狸
慢的
快的
棕色
黄色
绿色
发布于 2010-07-09 14:28:48
要了解如何以声明方式完成此操作(即不使用while循环),请参阅我研究的答案(有关所有内容的代码):Build an ASCII chart of the most commonly used words in a given text
请注意,该链接中的代码旨在使用尽可能少的字符,而不是可读的。请至少使用更具描述性的名称。
发布于 2010-07-09 00:35:49
我会尝试对每个返回的行运行一个拆分函数(用空格分隔每个单词),以便将所有单独的单词放入一个auxiliar表中。使用以下代码,您应该能够按空格拆分一行:
CREATE FUNCTION dbo.Split(@String varchar(8000), @Delimiter char(1))
returns @temptable TABLE (items varchar(8000))
as
begin
declare @idx int
declare @slice varchar(8000)
select @idx = 1
if len(@String)<1 or @String is null return
while @idx!= 0
begin
set @idx = charindex(@Delimiter,@String)
if @idx!=0
set @slice = left(@String,@idx - 1)
else
set @slice = @String
if(len(@slice)>0)
insert into @temptable(Items) values(@slice)
set @String = right(@String,len(@String) - @idx)
if len(@String) = 0 break
end
return
end您应该从游标或其他地方调用此函数;在它内部,只需使用如下内容:
insert into #tmp (word) select * from dbo.split(' ', @row)最后,您只需使用如下所示的简单查询:
select top 10 count(*) as number, word from separated_words_table order by numberSource here
发布于 2010-07-09 17:36:53
另一种方式。(“借用”自here)
WITH Sentences AS
(
SELECT 'quick brown fox' AS Sentence UNION ALL
SELECT 'slow yellow fox' UNION ALL
SELECT 'slow green fox'
),
Xmlified AS
(
SELECT
CAST('<M>' + REPLACE(Sentence,' ','</M><M>') + '</M>' AS XML) AS xSentence
FROM Sentences
),
Words AS
(
SELECT
Split.a.value('.', 'VARCHAR(100)') AS word
FROM Xmlified
CROSS APPLY xSentence.nodes('/M') Split(a)
)
SELECT COUNT(*) AS C, word FROM Words
GROUP BY word
ORDER BY C DESChttps://stackoverflow.com/questions/3205696
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