我有以下模型:
class Program(models.Model):
name = models.CharField(max_length = 128)
def __unicode__(self):
return self.name
class Cheat(models.Model):
program = models.ForeignKey(Program)
shortcut = models.CharField(max_length = 64)
description = models.CharField(max_length = 512)
def __unicode__(self):
return u"(%s) - %s" % (self.shortcut, self.description)
class Category(models.Model):
#program = models.ForeignKey(Program)
name = models.CharField(max_length = 128)
def __unicode__(self):
return self.name
class Sheet(models.Model):
program = models.ForeignKey(Program)
name = models.CharField(max_length = 128)
def __unicode__(self):
return self.name
class CategorizedCheat(models.Model):
order = models.IntegerField(unique = True)
sheet = models.ForeignKey(Sheet)
cheat = models.ForeignKey(Cheat)
category = models.ForeignKey(Category)
def __unicode__(self):
return unicode(self.cheat)在管理员中,我想要显示一个带有CategorizedCheats内联的工作表。问题是,我不能只有作弊,这是有关同一程序作为工作表。有没有办法用Sheet.program过滤这些内容?还是我的模型出了什么问题?
发布于 2010-07-06 03:24:25
在Django的admin中过滤ForeignKeys中的可用对象时,正确的答案几乎总是ModelAdmin.formfield_for_foreignkey:
http://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.formfield_for_foreignkey
那里的文档几乎完全解释了如何做你想做的事情。希望这能有所帮助!
发布于 2010-07-06 16:45:05
以下是最终的解决方案,感谢Gabriel:
def formfield_for_foreignkey(self, db_field, request, **kwargs):
if db_field.name == "cheat":
kwargs["queryset"] = Cheat.objects.filter(program=Sheet.objects.get().program)
return db_field.formfield(**kwargs)
return super(CategorizedCheatAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs)诀窍是使用Sheet.objects.get().program,这是我所缺少的信息。
https://stackoverflow.com/questions/3180838
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