我正在尝试创建一个返回一个值的函数。
在我的函数中,我有这样的脚本:
WITH t_new AS
(
SELECT PersIDOLD, PersIDNEW, RightsMUT,
SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp
FROM
(
SELECT h1.*,
CASE
WHEN h1.PersIDNEW = lag(h1.PersIDNEW)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
OR h1.PersIDOLD = lag(h1.PersIDOLD)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
THEN 0
ELSE 1
END gap
FROM HelpTable1 h1
)
)
SELECT PERSIDNEW, RIGHTSMUT
FROM t_new
WHERE grp =
(
SELECT grp FROM t_new WHERE PersIDNEW = 12 -- going to be a variable
)返回结果如下:
http://img59.imageshack.us/img59/6733/tablei.gif
现在我想返回row 3 coze,它在行RightsMUT中有一个1
我怎么能这样做呢?我试着用2 With来实现,但是oracle还不支持2。
发布于 2010-05-21 19:11:24
我的解决方案是:
WITH t_new AS
(
-- Alles durch gehen und
SELECT PersIDOLD, PersIDNEW, RightsMUT, SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp
FROM
(
SELECT h1.*,
CASE
WHEN h1.PersIDNEW = lag(h1.PersIDNEW) over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
OR h1.PersIDOLD = lag(h1.PersIDOLD) over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
THEN 0
ELSE 1
END gap
FROM LUTAXKT.HILFSTABELLE1UMSETZUNG h1
--WHERE h1.updateflag = 0
)
)
SELECT PersIDNEW, RightsMUT
FROM t_new
WHERE RightsMUT = 1 and
grp =
(
SELECT grp FROM t_new WHERE PersIDNEW = 12
)发布于 2010-05-21 18:19:22
让我试着猜测一下--请检查以下内容是否满足了您的需求:
WITH t_new AS
(
SELECT PersIDOLD, PersIDNEW, RightsMUT,
SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp
FROM
(
SELECT h1.*,
CASE
WHEN h1.PersIDNEW = lag(h1.PersIDNEW)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
OR h1.PersIDOLD = lag(h1.PersIDOLD)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
THEN 0
ELSE 1
END gap
FROM HelpTable1 h1
)
)
SELECT PERSIDNEW, RIGHTSMUT
FROM t_new
WHERE PersIDNEW = 12 AND RightsMUT = 1https://stackoverflow.com/questions/2881134
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