我正在成功地使用RJS在page.replace.html create.js.rjs上实现AJAX。我正在尝试更新两个位置,而不是一个位置,在观看了Ryan Bates Railscast之后,我非常接近(我认为),但我的/views/likes/create.js.rjs文件的语法有问题。情况是这样的:
位于/views/like/create.js.rjs的代码如下:
page.replace_html "votes_#{ @site.id }", :partial => @like
page.replace_html "counter", 10 - (@question.likes.count :conditions => {:user_id => current_user.id})
page[@like].visual_effect :highlight我的问题出在第二行。div "counter“在/views/question/show.html.erb页面中显示以下代码:
<div id="counter">
You have <%= 10 - (@question.likes.count :conditions => {:user_id => current_user.id}) %> votes remaining for this question
</div>从屏幕演员阵容来看,我认为我的错误与第二行的语法有关。他特别提到,您不能使用本地实例变量,但不确定如何进行更改。有什么想法?
更新:下面是我得到的错误:
ActionView::TemplateError (undefined method `likes' for nil:NilClass) on line #2 of app/views/likes/create.js.rjs:
1: page.replace_html "votes_#{ @site.id }", :partial => @like
2: page.replace_html "counter", 10 - (@question.likes.count :conditions => {:user_id => current_user.id})
3: page[@like].visual_effect :highlight
app/views/likes/create.js.rjs:2:in `_run_rjs_app47views47likes47create46js46rjs'
app/views/likes/create.js.rjs:1:in `_run_rjs_app47views47likes47create46js46rjs'
app/controllers/likes_controller.rb:8:in `create'
Rendered rescues/_trace (103.8ms)
Rendered rescues/_request_and_response (0.4ms)
Rendering rescues/layout (internal_server_error)更新:
类LikesController < ApplicationController
def create
@user = current_user
@site = Site.find(params[:site_id])
@like = @site.likes.create!(params[:like].merge(:user_id => @user.id))
respond_to do |format|
format.html { redirect_to @site}
format.js
end
end
end更新:以下是点赞表单:
<% remote_form_for [site, Like.new] do |f| %>
<%= f.hidden_field :site_name, :value => "#{site.name}" %>
<%= f.hidden_field :question_id, :value => @question.id %>
<%= f.hidden_field :ip_address, :value => "#{request.remote_ip}" %>
<%= f.hidden_field :like, :value => "1" %>
<%= submit_tag "^" , :class => 'voteup' %>
<% end %>发布于 2010-05-22 13:22:20
尝试这样获取@question,因为您的question_id将出现在params:like散列中
@question = Question.find params[:like][:question_id]无论如何,为了仔细检查,像这样打印您的参数,因此在likes_controller的创建操作中添加一条puts语句。
puts params.inspect,params[:like][:question_id]您在第2行有此错误(nil:NilClass的未定义方法‘line’)
这意味着您的@问题为空,您从未在您的创建操作中声明过此实例。
希望这对你有用。
发布于 2010-05-21 13:37:20
您将得到@question = nil。你应该勾选@ check is nil或@question.likes.count=0,如果是这样,你应该做(10-0),即
if //your condition here
page.replace_html "counter", "You have 10 votes remaining for this question"
else
page.replace_html "counter", 10 - (@question.likes.count :conditions => {:user_id => current_user.id})或
remaining_votes= (@question && !@question.likes.blank && @question.likes.count :conditions => {:user_id => current_user.id} !=0 )? @question.likes.count :conditions => {:user_id => current_user.id} : 0
page.replace_html "counter", "You have #{10-remaining_votes } votes remaining for this question"发布于 2010-05-21 21:22:58
在控制器中,你需要加载@question变量。
https://stackoverflow.com/questions/2879252
复制相似问题