我想使用jFugue在小程序中播放一些MIDI音乐。有一个用于MIDI模式的类- Pattern -加载模式的唯一方法是从文件。现在,我不知道applet是如何加载文件的,但我使用的是一个框架(PulpCore),它使加载资产成为一项简单的任务。如果我需要从ZIP目录中获取资产,我可以使用提供get()和getAsStream()方法的Assets类。get()以ByteArray的形式返回给定的资产,另一个以InputStream的形式返回。
我需要jFugue从ByteArray或InputStream加载模式。在伪代码中,我想这样做:
Pattern.load(new File(Assets.get("mymidifile.midi")));但是,没有可以接受ByteArray的文件构造函数。有什么建议吗?
发布于 2010-04-24 19:21:24
确实,jFugue只允许加载文件,这很遗憾,因为没有什么可以阻止使用任何其他类型的流:
public static final String TITLE = "Title";
public static Pattern loadPattern(File file) throws IOException {
InputStream in = new FileInputStream(file);
try {
return loadPattern(in);
} finally {
in.close();
}
}
public static Pattern loadPattern(URL url) throws IOException {
InputStream in = url.openStream();
try {
return loadPattern(in);
} finally {
in.close();
}
}
public static Pattern loadPattern(InputStream in) throws IOException {
return loadPattern(new InputStreamReader(in, "UTF-8")); // or ISO-8859-1 ?
}
public static Pattern loadPattern(Reader reader) throws IOException {
if (reader instanceof BufferedReader) {
return loadPattern(reader);
} else {
return loadPattern(new BufferedReader(reader));
}
}
public static Pattern loadPattern(BufferedReader bread) throws IOException {
StringBuffer buffy = new StringBuffer();
Pattern pattern = new Pattern();
while (bread.ready()) {
String s = bread.readLine();
if ((s != null) && (s.length() > 1)) {
if (s.charAt(0) != '#') {
buffy.append(" ");
buffy.append(s);
} else {
String key = s.substring(1, s.indexOf(':')).trim();
String value = s.substring(s.indexOf(':')+1, s.length()).trim();
if (key.equalsIgnoreCase(TITLE)) {
pattern.setTitle(value);
} else {
pattern.setProperty(key, value);
}
}
}
}
return pattern;
}更新(用于loadMidi)
public static Pattern loadMidi(InputStream in) throws IOException, InvalidMidiDataException
{
MidiParser parser = new MidiParser();
MusicStringRenderer renderer = new MusicStringRenderer();
parser.addParserListener(renderer);
parser.parse(MidiSystem.getSequence(in));
Pattern pattern = new Pattern(renderer.getPattern().getMusicString());
return pattern;
}
public static Pattern loadMidi(URL url) throws IOException, InvalidMidiDataException
{
MidiParser parser = new MidiParser();
MusicStringRenderer renderer = new MusicStringRenderer();
parser.addParserListener(renderer);
parser.parse(MidiSystem.getSequence(url));
Pattern pattern = new Pattern(renderer.getPattern().getMusicString());
return pattern;
}发布于 2010-04-24 19:07:10
如果我没记错的话,模式文件包含纯文本。使用getAsStream()加载文件,然后使用
BufferedReader br = new BufferedReader(new InputStreamReader(yourStream));
//...
String pattern = convertToString(br); // you should implement convertToString yourself. It's easy. Read the java.io APIs.其中yourStream是getAsStream()返回的InputStream。然后使用add(字符串...patterns)方法来加载模式:
add(pattern);发布于 2010-04-24 19:12:42
您可以使用以下代码(取自Pattern.loadPattern()方法的实现):
InputStream is = ...; // Get a stream from the Asset object
// Prepare a pattern object
Pattern pattern = new Pattern();
// Now start reaing from the stream
StringBuffer buffy = new StringBuffer();
BufferedReader bread = new BufferedReader(new InputStreamReader(is));
while (bread.ready()) {
String s = bread.readLine();
if ((s != null) && (s.length() > 1)) {
if (s.charAt(0) != '#') {
buffy.append(" ");
buffy.append(s);
} else {
String key = s.substring(1, s.indexOf(':')).trim();
String value = s.substring(s.indexOf(':')+1, s.length()).trim();
if (key.equalsIgnoreCase(TITLE)) {
pattern.setTitle(value);
} else {
pattern.setProperty(key, value);
}
}
}
}
bread.close();
pattern.setMusicString(buffy.toString());
// Your pattern is now readyhttps://stackoverflow.com/questions/2704151
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