我刚刚开始使用C++,所以如果这是一个愚蠢的问题,很抱歉。我有一个Braid类,它的成员是向量。我还没有写赋值运算符。当我对类型为Braid的对象进行大量赋值时,我遇到了内存问题:
0 0xb7daff89 in _int_malloc () from /lib/libc.so.6
#1 0xb7db2583 in malloc () from /lib/libc.so.6
#2 0xb7f8ac59 in operator new(unsigned int) () from /usr/lib/libstdc++.so.6
#3 0x0804d05e in __gnu_cxx::new_allocator<int>::allocate (this=0xbf800204, __n=1)
at /usr/lib/gcc/i686-pc-linux-gnu/4.4.3/../../../../include/c++/4.4.3/ext/new_allocator.h:89
#4 0x0804cb0e in std::_Vector_base<int, std::allocator<int> >::_M_allocate (this=0xbf800204, __n=1)
at /usr/lib/gcc/i686-pc-linux-gnu/4.4.3/../../../../include/c++/4.4.3/bits/stl_vector.h:140
#5 0x0804c086 in _Vector_base (this=0xbf800204, __n=1, __a=...)
at /usr/lib/gcc/i686-pc-linux-gnu/4.4.3/../../../../include/c++/4.4.3/bits/stl_vector.h:113
#6 0x0804b4b7 in vector (this=0xbf800204, __x=...)
at /usr/lib/gcc/i686-pc-linux-gnu/4.4.3/../../../../include/c++/4.4.3/bits/stl_vector.h:242
#7 0x0804b234 in Braid (this=0xbf800204) at braid.h:13
#8 0x080495ed in Braid::cycleBraid (this=0xbf8001b4) at braid.cpp:191
#9 0x080497c6 in Braid::score (this=0xbf800298, b=...) at braid.cpp:251
#10 0x08049c46 in Braid::evaluateMove (this=0xbf800468, move=1, pos=0, depth=2, b=...)我怀疑这些内存问题是因为向量正在调整大小。我想知道的是,当Braid类型的成员展开时,它的对象是否会自动展开?我正在写的代码真的很长,所以我会发布导致问题的部分。以下是代码的相关部分:
class Braid
{
private :
vector<int> braid; //Stores the braid.
int strands;
vector < vector<bool> > history;
vector < vector<bool> > CM;
public :
Braid () : strands(0) {}
Braid operator * (Braid);
Braid* inputBraid(int,vector<int>);
int printBraid();
int printBraid(vector<vector<int>::iterator>);
vector<int>::size_type size() const;
.....
.....
}以下是导致该问题的函数:-
int Braid::evaluateMove(int move,int pos,int depth,Braid b)
{
int netscore = 0;
Braid curr(*this);
curr = curr.move(move,pos);
netscore += curr.score(b);
while(depth > 1)
{
netscore += curr.evaluateMove(1,0,depth,b);
netscore += curr.evaluateMove(2,0,depth,b);
for(int i = 0; i < braid.size();++i)
{
netscore += curr.evaluateMove(3,i,depth,b);
netscore += curr.evaluateMove(4,i,depth,b);
netscore += curr.evaluateMove(5,i,depth,b);
curr = curr.cycleBraid();
netscore += curr.evaluateMove(6,0,depth,b);
}
--depth;
}
return netscore;
}发布于 2010-04-07 23:20:56
另一个问题:
while(depth > 1)
{
netscore += curr.evaluateMove(1,0,depth,b);
....
--depth;
}当深度大于1时,导致无休止的递归
发布于 2010-04-07 23:00:50
快速阅读:Braid curr(*this);导致复制。你不能用指针指向编织带吗?
发布于 2010-04-07 23:21:23
我是唯一标记堆栈溢出的人吗?
我涂掉了无用的部分(出于演示的目的)
int Braid::evaluateMove(int move,int pos,int depth,Braid b)
{
#int netscore = 0;
#Braid curr(*this);
#curr = curr.move(move,pos);
#netscore += curr.score(b);
while(depth > 1)
{
netscore += curr.evaluateMove(1,0,depth,b);
#netscore += curr.evaluateMove(2,0,depth,b);
#for(int i = 0; i < braid.size();++i)
#{
# netscore += curr.evaluateMove(3,i,depth,b);
# netscore += curr.evaluateMove(4,i,depth,b);
# netscore += curr.evaluateMove(5,i,depth,b);
# curr = curr.cycleBraid();
# netscore += curr.evaluateMove(6,0,depth,b);
#}
--depth;
}
return netscore;
}现在如果depth优于1..。oups
假设我这样做:
Braid b; b.evaluateMove(1,0,2,b);curr.evaluateMove(1,0,2,b);curr.evaluateMove(1,0,2,b);系统可能会耗尽内存。
注意:为什么evaluateMove既要复制this,又要Braid (参数b__)的副本?如果我是你,我会检查我的score方法。
https://stackoverflow.com/questions/2593471
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