计算time-1到time-2之间的时间？

Question

enter time-1 // eg 01:12
enter time-2 // eg 18:59

calculate: time-1 to time-2 / 12 
// i.e time between 01:12 to 18:59 divided by 12

如何在Python中做到这一点。我是一个初学者，所以我真的不知道从哪里开始。

编辑后补充说:我不想要计时器。time-1和time-2都由用户手动输入。

提前感谢您的帮助。

Answer 1

内置datetime模块中的datetime和timedelta类就是您所需要的。

from datetime import datetime

# Parse the time strings
t1 = datetime.strptime('01:12','%H:%M')
t2 = datetime.strptime('18:59','%H:%M')

# Do the math, the result is a timedelta object
delta = (t2 - t1) / 12
print(delta.seconds)

Answer 2

最简单和最直接的可能是：

def getime(prom):
  """Prompt for input, return minutes since midnight"""
  s = raw_input('Enter time-%s (hh:mm): ' % prom)
  sh, sm = s.split(':')
  return int(sm) + 60 * int(sh)

time1 = getime('1')
time2 = getime('2')

diff = time2 - time1

print "Difference: %d hours and %d minutes" % (diff//60, diff%60)

例如，典型的运行可能是：

$ python ti.py 
Enter time-1 (hh:mm): 01:12
Enter time-2 (hh:mm): 18:59
Difference: 17 hours and 47 minutes

Answer 3

这是一个计时器，用于对代码执行进行计时。也许你可以用它来做你想做的事。time()返回自1970-01-01 00:00:00以来的当前时间，单位为秒和微秒。

from time import time
t0 = time()
# do stuff that takes time
print time() - t0