blocks|key|1690186|text|$rnd1+=+rand(0,9);
do+{
++$rnd2+=+rand(0,9);
}+while+($rnd1+==+$rnd2);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1690187|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$rnd1 = rand(0,9);
do {
 $rnd2 = rand(0,9);
} while ($rnd1 == $rnd2);
</code></pre>

blocks|key|1656926|text|$r+=+str_shuffle("0123456789");
$r1+=+(int)+$r[0];
$r2+=+(int)+$r[1];|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1656927|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$r = str_shuffle("0123456789");
$r1 = (int) $r[0];
$r2 = (int) $r[1];
</code></pre>

blocks|key|250118|text|$random1+=+4;
$random2+=+5;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|250119|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$random1 = 4;
$random2 = 5;
</code></pre>

blocks|key|390951|text|$random1+=+(rand()+%25+10)
$random2+=+$random1+%2B+(rand()%259)%2B1+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|390952|在这种情况下，它们永远不会相等(因为至少1将被添加到$random1+)|unstyled|390953|如果两个数字都必须是从0到9，你只需要使用最后一个mod操作：|390954|$random1+=+(rand()+%25+10)
$random2+=+($random1+%2B+(rand()%259)%2B1+)+%2510+|390955|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$B|C]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>$random1 = (rand() % 10)
$random2 = $random1 + (rand()%9)+1 
</code></pre>

In this way they are never equal(as at least 1 will be added to $random1 )

if both number have to be from 0-9, you just have to do it with a last mod-operation:

<pre><code>$random1 = (rand() % 10)
$random2 = ($random1 + (rand()%9)+1 ) %10 
</code></pre>

blocks|key|391026|text|$numbers+=+array_rand(range(0,+9),+2);

echo+'<pre>';
print_r($numbers);
echo+'</pre>';|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|391027|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$numbers = array_rand(range(0, 9), 2);

echo '&lt;pre&gt;';
print_r($numbers);
echo '&lt;/pre&gt;';
</code></pre>

blocks|key|391745|text|function+random($min,+$max)+{
++++$stack+=+range($min,+$max);
++++shuffle($stack);+
++++$nr1+=+array_pop($stack);
++++$nr2+=+array_pop($stack);
++++return+array($nr1,+$nr2);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|391746|这可能会在不是数学高手的情况下做到这一点:)|unstyled|391747|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>function random($min, $max) {
 $stack = range($min, $max);
 shuffle($stack); 
 $nr1 = array_pop($stack);
 $nr2 = array_pop($stack);
 return array($nr1, $nr2);
}
</code></pre>

This might do the trick without being a math wiz :)

blocks|key|1690245|text|我想你会发现rand()%259会给你一个介于0和8之间的数字。如果需要0到9(包括0和9)，则应使用rand()%2510。我假设这就是你想要的，但如果从0到8是你真正想要的，你可以很容易地调整答案。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1690246|如果您想在该范围内生成两个数字，最简单的方法是在该范围内生成一个数字，然后在小于该范围的一个范围内生成另一个数字，如果该数字相等或大于该范围，则递增该数字。|1690247|这是一种数学方法，而且是确定性的(无论如何，总是两次调用rand()+)。虽然不太可能，但真正的随机数生成器可以生成完全相同的数字字符串，这将使循环解决方案变得不明智(您可能会使用线性生成器，所以这可能不是问题)。|1690248|第一次尝试时，您有完整的范围可供选择(从0到9的10个数字)。在第二种情况下，您得到的是整个范围减去已经选择的数字。因此，如果您的第一个数字是7，您将生成一个从0到8的数字，并将7映射到8，将8映射到9：|1690249|$random1+=+(rand()+%25+10);
$random2+=+(rand()+%25+9);
if+$random2+>=+$random1+{
++++$random2+=+$random2+%2B+1;
}|code-block|syntax|javascript|1690250|entityMap^0|6|8|1D|9|0|0|S|6|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|11|8|@]|D|@]|E|$]]|$1|L|3|M|5|N|7|12|8|@]|D|@]|E|$O|P]]|$1|Q|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|R|$]]

I think you'll find that <code>rand()%9</code> will give you a number in the range 0 through 8 inclusive. If you want 0 through 9 inclusive, you should use <code>rand()%10</code>. I'm going to assume that's what you wanted but you could adjust the answer easily if 0 through 8 was what you really intended.

If you want two numbers in that range, the easiest way is to generate one in that range then generate another in one less than that range and, if it's identical or greater, increment it.

This is the mathematical way to do it, and it's deterministic (always two calls to <code>rand()</code> no matter what). Although unlikely, a true random number generator could produce a string of numbers all identical which would make the looping solutions unwise (you're likely to be using a linear generator so this probably won't be a problem).

On the first attempt, you have the full range to choose from (10 numbers, 0 through 9). On the second you have the full range minus the number already chosen. So, if your first number was 7, you generate a number from 0 through 8 and map 7 to 8 and 8 to 9:

<pre><code>$random1 = (rand() % 10);
$random2 = (rand() % 9);
if $random2 &gt;= $random1 {
 $random2 = $random2 + 1;
}
</code></pre>

blocks|key|1656770|text|如果你只是想要唯一的数字，只要从零开始，每个新数字加%2B1即可。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1656771|如果你需要随机的唯一数字，只需将你之前的数字保存在一个列表中，当你需要一个新的数字时，只需生成随机数字，直到你找到一个不在该列表中的数字。|1656772|如果需要唯一标识符，可以使用内置函数uniqid。|offset|length|style|CODE|1656773|entityMap|0|LINK|mutability|MUTABLE|url|http://us2.php.net/uniqid^0|0|0|I|6|I|6|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|T|8|@$F|U|G|V|H|I]]|9|@$F|W|G|X|1|Y]]|A|$]]|$1|J|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|K|$L|$5|M|N|O|A|$P|Q]]]]

If you simply want unique numbers, just start at zero and add +1 for every new number.

If you need random unique numbers, just save your previous numbers in a list and when you need a new one, just generate random numbers until you found one, which is not in that list.

If you need unique identifiers, you can use the built-in function <a href="http://us2.php.net/uniqid" rel="nofollow noreferrer"><code>uniqid</code></a>.

blocks|key|1692419|text|$r+=+mt_rand(0,+9);
$r2+=+($r+%7C%7C+$r+===+9)+?+$r-1+:+$r%2B1;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1692420|解释：|unstyled|1692421|$r：从0到9的数字。|offset|length|style|CODE|1692422|$r2：总是从0到9，除了$r-1或$r%2B1|1692423|更随机的方式是生成2个数字：|1692424|$r+=+mt_rand(0,+9);
$r2+=+mt_rand(0,+9);
$r2+=+$r!==$r2+?+$r2+:+(($r+%7C%7C+$r+===+9)+?+$r-1+:+$r%2B1);|1692425|另外，如果您使用的是PHP+7%2B，则可以将mt_rand更改为random_int。|1692426|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.mt-rand.php|1|http://php.net/manual/en/function.random-int.php^0|0|0|0|2|0|0|3|D|4|I|4|0|0|0|L|7|0|V|A|1|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|15|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|16|8|@$I|17|J|18|K|L]]|9|@]|A|$]]|$1|M|3|N|5|F|7|19|8|@$I|1A|J|1B|K|L]|$I|1C|J|1D|K|L]|$I|1E|J|1F|K|L]]|9|@]|A|$]]|$1|O|3|P|5|F|7|1G|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1H|8|@]|9|@]|A|$B|C]]|$1|S|3|T|5|F|7|1I|8|@]|9|@$I|1J|J|1K|1|1L]|$I|1M|J|1N|1|1O]]|A|$]]|$1|U|3|-4|5|F|7|1P|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]|12|$5|X|Y|Z|A|$10|13]]]]

<pre><code>$r = mt_rand(0, 9);
$r2 = ($r || $r === 9) ? $r-1 : $r+1;
</code></pre>

Explain:

<code>$r</code>: it's number from 0 to 9.

<code>$r2</code>: it's allways from 0 to 9 but <code>$r-1</code> or <code>$r+1</code>

More randomly way is generate 2 numbers:

<pre><code>$r = mt_rand(0, 9);
$r2 = mt_rand(0, 9);
$r2 = $r!==$r2 ? $r2 : (($r || $r === 9) ? $r-1 : $r+1);
</code></pre>

Also if you using PHP 7+ you can change <a href="http://php.net/manual/en/function.mt-rand.php" rel="nofollow">mt_rand</a> to <a href="http://php.net/manual/en/function.random-int.php" rel="nofollow">random_int</a>

blocks|key|391050|text|Alix+Axel的解决方案是最简单的，对我来说效果也很好。我想要现有数组中的三个随机条目，所以我使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|391051|$rands+=+array_rand(range(0,count($otherarray)),3);|code-block|syntax|javascript|391052|然后显示关键字在$rands中的条目。|offset|length|style|CODE|391053|entityMap^0|0|0|8|6|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Alix Axel's solution was the most straightforward and worked fine for me. I wanted three random entries from an existing array, so I used

<pre><code>$rands = array_rand(range(0,count($otherarray)),3);
</code></pre>

And then displayed entries for which the key was in <code>$rands</code>.

blocks|key|390971|text|很难解释你的问题，看起来你想伪随机地生成0到9之间的两个不同的整数？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|390972|所以生成第一个，生成另一个，如果它与第一个相同，直到它不是。|390973|我断言，在没有正当理由的情况下，这将与任何其他方法一样有效。|390974|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

Interpreting your question rather heavily it looks like you want to pseudo-randomly generate 2 different integers between 0 and 9 inclusive?

So generate the first, generate another, if it's the same as the first repeat until it isn't.

I assert, without justification, that this will be as efficient as any other method.

blocks|key|1692328|text|$random1+=+rand()+%25+9;
$random2+=+($random1+%2B+1)+%25+9;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1692329|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>$random1 = rand() % 9;
$random2 = ($random1 + 1) % 9;
</code></pre>

blocks|key|1692406|text|$random_numbers+=+array();
for+($i+=+0;+$i+<=+1;+$i%2B%2B)
{
++$random_numbers[$i]+=+rand(1,13);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1692407|我解决这个问题的方法是将rand放在一个数组中，放在一个for循环中。这样我就得到了两个不同的随机数！这两个数字放在数组中的两个字段中，即random_numbers[0]和random_numbers[1]|unstyled|offset|length|style|CODE|1692408|entityMap^0|0|C|4|1X|H|2F|H|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]|$G|S|H|T|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|U|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>$random_numbers = array();
for ($i = 0; $i &lt;= 1; $i++)
{
 $random_numbers[$i] = rand(1,13);
}
</code></pre>

I solved it by putting the <code>rand</code> inside an array inside a for loop. This way I got two different random numbers! The two numbers are placed in the array in two fields, <code>random_numbers[0]</code> and <code>random_numbers[1]</code>

I need to generate two numbers that are NOT equal in PHP.

I know that I use <code>$random1 = (rand()%9);</code> to generate random a number between 0-9. I need to add something to this I guess.

Thanks!

Generate two numbers that are NOT equal in PHP

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我需要生成两个在PHP中不相等的数字。我知道我使用$random1 = (rand()%9);生成一个介于0-9之间的随机数。我想我需要在这上面添加一些东西。谢谢!

问生成两个在PHP中不相等的数字
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