在循环中从XMLList添加/删除

Question

我正在尝试解析通过HTTPService中的e4x检索到的一些XML。循环起作用了，对于列表中的每一集，它都会经过循环。然而，当它试图附加到一个XMLList时，我得到了下面的错误。

TypeError: Error #1009: Cannot access a property or method of a null object reference.

我正在尝试查询本地SQLite数据库，看看剧集是否存在(正在工作)，如果存在，则附加到一个xmllist，如果不存在，则附加到另一个xmllist。

public static function seasonFavHandler(evt:ResultEvent):void {
    Application.application.ManagePage.selectedShow = 
        Application.application.ManagePage.gridFavourites.selectedItem as XML;
    episodeNumber = XML(evt.result).descendants("episode");
    var episode:Object = episodeNumber;
    for each(episode in episodeNumber) {
        currentEpisode = episode as XML;
        achkStatement = new SQLStatement();
        achkStatement.sqlConnection = dbconnection;
        achkStatement.text = "select :episodename from episodes where episodename = :episodename";
        achkStatement.parameters[":episodename"] = episode.title;
        achkStatement.addEventListener(SQLEvent.RESULT, episodeHandler);
        achkStatement.execute();
        trace(episode.title);
    }
   //Application.application.ManagePage.episodeList = episodeNumber;
   seasonHttpService.removeEventListener(ResultEvent.RESULT, seasonFavHandler);
   CursorManager.removeBusyCursor();
}

private static function episodeHandler(event:SQLEvent):void {
    var result:SQLResult = achkStatement.getResult();
    var episodeNewT:XMLList;
    var episodeWatchedT:XMLList;
    if (!result.data) {
        episodeNewT.appendChild(currentEpisode);
        //Application.application.ManagePage.gridUnwatched.addChild(currentEpisode);
    } else {
        episodeWatchedT.appendChild(currentEpisode);
        //Application.application.ManagePage.gridWatched.addChild(currentEpisode);
    }
    Application.application.ManagePage.episodeNew = episodeNewT;
    Application.application.ManagePage.episodeWatched = episodeWatchedT;
    achkStatement.removeEventListener(SQLEvent.RESULT, episodeHandler);
}

Answer 1

您已经声明了episodeNewT和episodeWatchedT，但是还没有实例化它们。我还建议您使用XMLListCollection而不是XMLList，因为它在运行时更容易修改。

试试这个：

var episodeNewT:XMLListCollection = new XMLListCollection();
var episodeWatchedT:XMLListCollection = new XMLListCollection();

if (!result.data) {
    episodeNewT.addItem(currentEpisode);
} else {
    episodeWatchedT.addItem(currentEpisode);
}

Application.application.ManagePage.episodeNew = episodeNewT.copy();
Application.application.ManagePage.episodeWatched = episodeWatchedT.copy();

现在，您的变量将不为空，您可以将其追加到它们之后。注意，您将在最后使用copy()将XMLListCollection转换回XMLList。

Answer 2

这是我对动态地将xml节点添加到xmllist中的解决方案。

private function addXmlChild(xmlList:XMLList, xmlNode:XML):void
{
    try
    {
        if(xmlList.children().length() != 0)
        {
            xmlList[xmlList.length() + 1] = xmlNode;
        }
        else
            xmlList[0] = xmlNode;               
        } 
        catch(error:Error) 
        {
            LogWriter.ErrorLog("addXmlChild, " + error.message);
        }
}

Answer 3

但是如果你想使用XMLList，你可以尝试下一步：

var episodeNewT:XMLList;
var episodeWatchedT:XMLList;
if (!result.data) {
    episodeNewT= XMLList(currentEpisode);
    //Application.application.ManagePage.gridUnwatched.addChild(currentEpisode);
} else {
    episodeWatchedT = XMLList(currentEpisode);
    //Application.application.ManagePage.gridWatched.addChild(currentEpisode);
}