如何在Firefox中使用于IE的http通过可插拔协议工作?
或者,如何为Firefox开发一个?任何例子都将不胜感激。
谢谢。
发布于 2009-11-30 21:51:49
编写一个实现nsIObserver的XPCOM对象。然后为http-on-modify-request和http-on-examine response创建监听器。
var myObj = new MyObserver(); //implements nsIObserver
var observerService = Components.classes["@mozilla.org/observer-service;1"].getService(Components.interfaces.nsIObserverService);
observerService.addObserver(myObj "http-on-modify-request", false);
observerService.addObserver(myObj, "http-on-examine-response", false);发布于 2009-11-15 19:33:29
在火狐上,如果你想以一种“可插拔”的方式绕过默认行为,你可以写一个NPAPI based plugin。假设关于这个主题的文档很少……但是要想让你开始,你可以咨询this。
有了NPAPI插件,你就可以访问整个操作系统,因此可以自由地向Firefox公开任何其他资源。
发布于 2015-07-23 17:08:17
编写一个实现nsIProtocolHandler的XPCOM对象。例如,您可以从网页访问本地图像:
const Cu = Components.utils;
const Ci = Components.interfaces;
const Cm = Components.manager;
const Cc = Components.classes;
Cu.import("resource://gre/modules/XPCOMUtils.jsm");+
Cu.import("resource://gre/modules/FileUtils.jsm");
Cu.import("resource://gre/modules/NetUtil.jsm");
/***********************************************************
class definition
***********************************************************/
function sampleProtocol() {
// If you only need to access your component from JavaScript,
//uncomment the following line:
this.wrappedJSObject = this;
}
sampleProtocol.prototype = {
classDescription: "LocalFile sample protocol",
classID: Components.ID("{XXXXXXXX-XXXX-XXXX-XXXX-XXXXXXXXXXXX}"),
contractID: "@mozilla.org/network/protocol;1?name=x-localfile",
QueryInterface: XPCOMUtils.generateQI([Ci.nsIProtocolHandler]),
//interface nsIProtocolHandler
allowPort :function(port, scheme)
{
if ((port == 80)&&(scheme == x-localfile)) {
return true;
}
else
{
return false;
}
},
newChannel: function(aURI)
{
// Just example. Implementation must parse aURI
var file = new FileUtils.File("D:\\temp\\getImage.jpg");
var uri = NetUtil.ioService.newFileURI(file);
var channel = NetUtil.ioService.newChannelFromURI(uri);
return channel;
},
newURI(aSpec, aOriginCharset, aBaseURI)
{
//URI looks like x-localfile://example.com/image1.jpg
var uri = Cc["@mozilla.org/network/simple-uri;1"].createInstance(Ci.nsIURI);
uri.spec = aSpec;
return uri;
},
scheme: "x-localfile",
defaultPort: 80,
protocolFlags: 76
};
var components = [sampleProtocol];
if ("generateNSGetFactory" in XPCOMUtils)
var NSGetFactory = XPCOMUtils.generateNSGetFactory(components); // Firefox 4.0 and higher
else
var NSGetModule = XPCOMUtils.generateNSGetModule(components); // Firefox 3.x要小心!此方法可能会创建漏洞
https://stackoverflow.com/questions/1670398
复制相似问题