重写的问题:
HOMEDIR="ftpuser"
REMOTEIP="1.1.1.1"
MYSQLPASS="password"
Q1="DROP USER "$HOMEDIR"_shop;"
Q2="DROP DATABASE "$HOMEDIR"_shop;"
Q3="CREATE DATABASE IF NOT EXISTS "$HOMEDIR"_shop;"
Q4="GRANT ALL ON "$HOMEDIR"_shop TO '"$HOMEDIR"_shop'@'localhost' IDENTIFIED BY '$MYSQLPASS';"
Q5="GRANT ALL ON "$HOMEDIR"_shop TO '"$HOMEDIR"_shop'@'anotherip' IDENTIFIED BY '$MYSQLPASS';"
# Need to grant permissions from another server as well
Q6="FLUSH PRIVILEGES;"
SQL="${Q1}${Q2}${Q3}${Q4}${Q5}${Q6}"
echo $SQL
echo " "
ssh -p 8899 root@$REMOTEIP "mysql -u root -p "$SQL""然后我运行:
/root/testing/migratesite.sh并获取:
bash: DROP: command not found
bash: CREATE: command not found
bash: GRANT: command not found
bash: GRANT: command not found
bash: FLUSH: command not found我遗漏了什么?
发布于 2009-11-03 20:20:07
您缺少引号和正确的mysql客户端命令行:
ssh -p 8899 root@$REMOTEIP "mysql -u root -p -e \"$SQL\""您需要转义$SQL变量两边的引号,以便将它们传递给远程shell,否则它们将由本地shell解释(这就是为什么会出现DROP: command not found,分号由shell解释)。此外,要让mysql客户端执行命令,您必须传递-e命令行选项。
发布于 2009-11-03 20:20:32
你有没有试过这个:
ssh -p 8899 root@$REMOTEIP "echo \"$SQL\" | mysql -u root --password=$SQL_PASS"https://stackoverflow.com/questions/1666848
复制相似问题