谷歌地图，cellid to location

Question

根据此示例：

http://www.codeproject.com/KB/mobile/DeepCast.aspx

在发送单元It信息(MCC、MNC、towerid等)时，可以请求包含范围的gps坐标(经度和纬度)

有人能告诉我请求/post到这个地址的实际参数是什么吗？

http://www.google.com/glm/mmap

可能是这样的

http://www.google.com/glm/mmap?mcc=xxx&mnc=xxx&towerid=xxx

我想知道我们会得到什么回应。

我观察了OpenCellid网站，他们提供了一些很好的应用程序接口开始，但我也想知道在谷歌地图(因为他们有更完整的数据库)。

OpenCellID API

Answer 1

以下是使用的示例

#!/usr/bin/python

country = 'fr'
#device = 'Sony_Ericsson-K750'
device = "Nokia N95 8Gb"
user_agent = 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)'
mmap_url = 'http://www.google.com/glm/mmap'
geo_url = 'http://maps.google.com/maps/geo'

from struct import pack, unpack
from httplib import HTTP
import urllib2

def fetch_latlong_http(query):
    http = HTTP('www.google.com', 80)
    http.putrequest('POST', '/glm/mmap')
    http.putheader('Content-Type', 'application/binary')
    http.putheader('Content-Length', str(len(query)))
    http.endheaders()
    http.send(query)
    code, msg, headers = http.getreply()
    result = http.file.read()
    return result

def fetch_latlong_urllib(query):
    headers = { 'User-Agent' : user_agent }
    req = urllib2.Request(mmap_url, query, headers)
    resp = urllib2.urlopen(req)
    response = resp.read()
    return response

fetch_latlong = fetch_latlong_http

def get_location_by_cell(cid, lac, mnc=0, mcc=0, country='fr'):
    b_string = pack('>hqh2sh13sh5sh3sBiiihiiiiii',
                    21, 0,
                    len(country), country,
                    len(device), device,
                    len('1.3.1'), "1.3.1",
                    len('Web'), "Web",
                    27, 0, 0,
                    3, 0, cid, lac,
                    0, 0, 0, 0)

    bytes = fetch_latlong(b_string)
    (a, b,errorCode, latitude, longitude, c, d, e) = unpack(">hBiiiiih",bytes)
    latitude = latitude / 1000000.0
    longitude = longitude / 1000000.0

    return latitude, longitude

def get_location_by_geo(latitude, longitude):
    url = '%s?q=%s,%s&output=json&oe=utf8' % (geo_url, str(latitude), str(longitude))
    return urllib2.urlopen(url).read()

if __name__ == '__main__':
    print get_location_by_cell(20465, 495, 3, 262)
    print get_location_by_cell(20442, 6015)
    print get_location_by_cell(1085, 24040)
    print get_location_by_geo(40.714224, -73.961452)
    print get_location_by_geo(13.749113, 100.565327)

Answer 2

你可以使用火狐使用的Google Location API (示例见http://www.mozilla.com/en-US/firefox/geolocation/ )，其url为www.google.com/loc/json/。实际上，这是基于JSON的Perl服务，最小的Perl示例如下所示：

use LWP;

my $ua = LWP::UserAgent->new;
$ua->agent("TestApp/0.1 ");
$ua->env_proxy();

my $req = HTTP::Request->new(POST => 'https://www.google.com/loc/json');

$req->content_type('application/jsonrequest');
$req->content('{"cell_towers": [{"location_area_code": "8721", "mobile_network_code": "01", "cell_id": "7703", "mobile_country_code": "262"}], "version": "1.1.0", "request_address": "true"}');

# Pass request to the user agent and get a response back
my $res = $ua->request($req);

# Check the outcome of the response
if ($res->is_success) {
    print $res->content;
} else {
    print $res->status_line, "\n";
    return undef;
}

请记住，谷歌还没有正式开放此API用于其他用途...

Answer 3

Google location API的新位置如下：https://developers.google.com/maps/documentation/geolocation/intro

使用此API，您可以从Cell信息(cellid、mcc、mnc和lac)中检索位置