将原始时间和tzinfo转换为UTC时间的正确方法是什么?假设我有:
d = datetime(2009, 8, 31, 22, 30, 30)
tz = timezone('US/Pacific')第一种方式,由pytz启发:
d_tz = tz.normalize(tz.localize(d))
utc = pytz.timezone('UTC')
d_utc = d_tz.astimezone(utc)第二种方式,来自UTCDateTimeField
def utc_from_localtime(dt, tz):
dt = dt.replace(tzinfo=tz)
_dt = tz.normalize(dt)
if dt.tzinfo != _dt.tzinfo:
# Houston, we have a problem...
# find out which one has a dst offset
if _dt.tzinfo.dst(_dt):
_dt -= _dt.tzinfo.dst(_dt)
else:
_dt += dt.tzinfo.dst(dt)
return _dt.astimezone(pytz.utc)不用说,这两种方法在相当多的时区产生不同的结果。
问题是-什么是正确的方式?
发布于 2009-08-31 16:07:41
您的第一个方法似乎是经过批准的方法,并且应该是DST感知的。
您可以稍微缩短它,因为pytz.utc = pytz.timezone('UTC'),但您已经知道这一点:)
tz = timezone('US/Pacific')
def toUTC(d):
return tz.normalize(tz.localize(d)).astimezone(pytz.utc)
print "Test: ", datetime.datetime.utcnow(), " = ", toUTC(datetime.datetime.now())发布于 2014-10-04 15:25:02
将原始时间和tzinfo转换为utc时间的正确方法是什么?
This answer enumerates some issues with converting a local time to UTC
from datetime import datetime
import pytz # $ pip install pytz
d = datetime(2009, 8, 31, 22, 30, 30)
tz = pytz.timezone('US/Pacific')
# a) raise exception for non-existent or ambiguous times
aware_d = tz.localize(d, is_dst=None)
## b) assume standard time, adjust non-existent times
#aware_d = tz.normalize(tz.localize(d, is_dst=False))
## c) assume DST is in effect, adjust non-existent times
#aware_d = tz.normalize(tz.localize(naive_d, is_dst=True))
# convert to UTC
utc_d = aware_d.astimezone(pytz.utc)发布于 2009-08-31 15:18:23
使用第一种方法。没有理由重新发明时区转换的轮子
https://stackoverflow.com/questions/1357711
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