ProcessInfo和RedirectStandardOutput

Question

我有一个应用程序，它在命令窗口中调用另一个进程，该进程具有输出到控制台窗口的更新统计信息。我认为这是一个相当简单的操作，但我似乎不能让它工作。我是不是遗漏了什么？

string assemblyLocation = Assembly.GetExecutingAssembly().Location;

Process process = new Process
{
    ProcessStart =
    {
        RedirectStandardOutput = true,
        UseShellExecute = false,
        WindowStyle = ProcessWindowStyle.Hidden,
        Arguments = arg,
        FileName = assemblyLocation.Substring(0, assemblyLocation.LastIndexOf("\\")) + "\\ffmpeg.exe",
        CreateNoWindow = true
    }
};

process.Start();

Console.WriteLine(process.StandardOutput.ReadToEnd());

process.WaitForExit();

理想情况下，我希望的是，当我点击的进程中的输出发生变化，或者数据进入阅读器时，我可以从中获取事件。

任何帮助都是很好的，我觉得这是一个新手问题，但似乎遗漏了一些东西。

Answer 1

我以前也经历过这种情况。有时，您调用的进程输出到控制台的方式与这种输出重定向不兼容。在这种情况下，我很幸运能够修改外部进程来解决这个问题。

您可以尝试在另一个输出到控制台的进程上运行代码，并查看它是否正常工作。它现在正在读给我听。

编辑：

我取了一个我用来做这件事的代码块。这是在一个WPF应用程序中，它将进程输出重定向到窗口。注意事件绑定。因为这是WPF，所以我必须调用我的调用来写出数据。既然你不担心阻塞，你应该能够简单地将其替换为：

Console.WriteLine(e.Data);

希望它能帮上忙！

    private static void LaunchProcess()
    {
        Process build = new Process();
        build.StartInfo.WorkingDirectory =  @"dir";
        build.StartInfo.Arguments = "";
        build.StartInfo.FileName = "my.exe";

        build.StartInfo.UseShellExecute = false;
        build.StartInfo.RedirectStandardOutput = true;
        build.StartInfo.RedirectStandardError = true;
        build.StartInfo.CreateNoWindow = true;
        build.ErrorDataReceived += build_ErrorDataReceived;
        build.OutputDataReceived += build_ErrorDataReceived;
        build.EnableRaisingEvents = true;
        build.Start();
        build.BeginOutputReadLine();
        build.BeginErrorReadLine();
        build.WaitForExit();
    }

    // write out info to the display window
    static void build_ErrorDataReceived(object sender, DataReceivedEventArgs e)
    {
        string strMessage = e.Data;
        if (richTextBox != null && !String.Empty(strMessage))
        {
            App.Instance.Dispatcher.BeginInvoke(DispatcherPriority.Send, (ThreadStart)delegate()
            {
                Paragraph para = new Paragraph(new Run(strMessage));
                para.Margin = new Thickness(0);
                para.Background = brushErrorBrush;
                box.Document.Blocks.Add(para);
            });
       }
    } 

Answer 2

我不确定您到底遇到了什么问题，但是如果您希望在输出生成后立即采取行动，请尝试挂钩到进程的OutputDataReceived事件。您可以指定处理程序从进程异步接收输出。我已经成功地使用了这种方法。

Process p = new Process();
ProcessStartInfo info = p.info;
info.UseShellExecute = false;
info.RedirectStandardOutput = true;
info.RedirectStandardError = true;

p.OutputDataReceived += p_OutputDataReceived;
p.ErrorDataReceived += p_ErrorDataReceived;

p.Start();

p.BeginOutputReadLine();
p.BeginErrorReadLine();
p.WaitForExit();

。。

void p_OutputDataReceived(object sender, DataReceivedEventArgs e)
{
  Console.WriteLine("Received from standard out: " + e.Data);
}

void p_ErrorDataReceived(object sender, DataReceivedEventArgs e)
{
  Console.WriteLine("Received from standard error: " + e.Data);
}

有关详细信息，请参阅OutputDataReceived事件关闭过程。

Answer 3

使用lambda表达式等：

var info = new ProcessStartInfo(path)
{
    RedirectStandardError = true,
    RedirectStandardOutput = true,
    UseShellExecute = false,
    Verb = "runas",
};

var process = new Process
{
    EnableRaisingEvents = true,
    StartInfo = info
};

Action<object, DataReceivedEventArgs> actionWrite = (sender, e) =>
{
    Console.WriteLine(e.Data);
};

process.ErrorDataReceived += (sender, e) => actionWrite(sender, e);
process.OutputDataReceived += (sender, e) => actionWrite(sender, e);

process.Start();
process.BeginOutputReadLine();
process.BeginErrorReadLine();
process.WaitForExit();