Hang Man中的分数计算:Java代码

Question

我用Java.But写了一个Hang Man游戏的代码，我写不出合适的代码，也找不到计算用户分数的方法，并在用户端打印出来，用0:stop.Here命令是分数计算规则；

分数的计算方法是单词的字母数减去当前显示的字母数。这里的“表”分数是5-4=1，因为当用户猜测时，已经显示了4个字母。

如果用户猜测不正确，分数为0如果在猜测之前完成了男子的图形，则分数为0

同一用户玩游戏的每一次都是一个会话，同一个词不能被计算机容纳。如果“表”是作为“事物”持有的，那么它就不能在同一会话中被计算机再次持有。

当用户在主菜单中按0时，会话结束。

播放次数、正确猜测次数和用户总分都会显示在屏幕上。

此外，我有一个问题，以防止随机选择的单词数组中的重复

import java.util.Random;
import java.util.Scanner;
public class CEVIK_CAGATAY{
    public static char[] star;
        public static void main (String args[])
        {   
            char game[];
            int category;
            int correct=0;
            Scanner input = new Scanner(System.in);
            Random r = new Random();
            int totalplay=0;
            int totalscore=0;
            String man[] = new String[7];
            man[2] = " --\n o |\n/  |\n   |\n_____\n";
            man[3] = " --\n o |\n/| |\n   |\n_____\n";
            man[4] = " --\n o |\n/|\\|\n   |\n_____\n";
            man[5] = " --\n o |\n/|\\|\n/  |\n_____\n";
            man[6] = " --\n o |\n/|\\|\n/ \\|\n_____\n";
            String arr[]={"serhat","cagatay","begum","emre","berk","ali","veli","istanbul",
            "ankara","mersin","izmir","antalya","new york","samsun","kedi","kopek",
            "kus","ayi","bocek","karinca","manda","masa","pencil","bag","clock","televison","book","glass"};
            int arr1 []={6,7 };


            System.out.println("0 To Stop,1 to Continue");
            category=input.nextInt();



            while(category!=0){


            System.out.println("0 To STop,1 to Continue"); 








        String word = arr[r.nextInt(arr.length)];
            for(int i=0; i<arr.length;i++) {
                if(arr[i]==word){
                    int letterlength=arr1[i];
                }
                //letterlength-existedlength=guessremain;


            }
            int count = word.length();
            char[] CharArr=word.toCharArray(); 
            char[] star = word.toCharArray();
        for(int i=0;i<star.length;i++)
        {
            star[i] = '*';
            System.out.print(star[i]);

        }


        for (int i=1; i<=5; i++)
        {
            System.out.printf ("\nGuess a Letter:");
            char letter= input.next().charAt(0);

            for (int j=0;j<CharArr.length; j++)
            {
                if(letter == star[j])
                {
                    System.out.println("this word already exist");
                }
                else
        {
                    if(letter==CharArr[j])
                    {
                        star[j]=letter;
                        i--;
                        System.out.printf("CORRECT GUESS!\n");
                        correct++;
                    }
                }
            }
            System.out.print(star);
            switch(i+0)
            {
                    case 1: System.err.printf("Strike 1\n");
                    System.out.println(man[2]);
                        break;
                    case 2: System.err.printf("Strike 2\n");
                    System.out.println(man[3]);
                        break;
                    case 3: System.err.printf("Strike 3\n");
                    System.out.println(man[4]);
                    break;
                    case 4: System.err.printf("Strike 4\n");
                    System.out.println(man[5]);
                    break;
                    case 5: System.err.printf("Strike5\n");


                        System.err.printf("You're out!!! The word is Not_Matched\n");
                        System.out.println(man[6]);
                        break;
            }   


            System.out.printf("\n");
            if((new String(word)).equals(new String(star))) 
            {
                System.err.printf("Winner Winner\n");
                break;
            }
        }
        totalplay++;
        totalscore+=correct;
        System.out.println("CONTINUE 1,STOP 0");
        category=input.nextInt();
        if(category==0) {
            System.out.println(totalplay);
            System.out.println(totalscore);
        }

    }

            }


        }

Answer 1

去掉以下for循环。除了抛出数组索引越界错误外，它没有任何用途。您的程序在没有它的情况下运行。也要确保实践语言的最佳实践(例如用于命名变量的camelCase )。它使人们更容易理解您的代码。

for(int i=0; i<arr.length;i++) {
    if(arr[i]==word){
        int letterlength=arr1[i];
    }
    //letterlength-existedlength=guessremain;
}