实际上,我是angularJS的新手,我的场景是:
$rootScope.synchronization = function($scope, $rootScope, $window, $http)
{
if(localStorage.getItem('job_id') != "" && localStorage.getItem('job_id') > 0)
{
alert("found job id!");
console.log(localStorage.getItem('job_id'));
if(localStorage.getItem('job_id.done_tasks') != "" && localStorage.getItem('job_id.done_tasks') > 0)
{
alert("found done tasks ids!");
console.log(localStorage.getItem('job_id.done_tasks'));
$scope.done_tasks = {};
$scope.done_tasks = localStorage.getItem('job_id.done_tasks');
$scope.job_id = localStorage.getItem('job_id');
console.log($scope.done_tasks);
var userData = $http(
{
method: "post",
url: "http://localhost/t-app/mobile-data/update-tasks.php",
data: {
done_tasks : $scope.done_tasks,
job_id: $scope.job_id,
},
headers: { 'Content-Type': 'application/x-www-form-urlencoded' }
});
userData.success(function (userdataobject)
{
$rootScope.status_id = userdataobject["status_id"];
$rootScope.message = userdataobject["message"];
localStorage.setItem('job_id', '');
localStorage.setItem('job_id.done_tasks', '');
})
}
console.log(localStorage.getItem('job_id'));
console.log(localStorage.getItem('job_id'));
}
};在我的控制器中,我使用的是:
$interval( $rootScope.synchronization, 2000 , 1);现在我得到了这个错误:
Error: [$rootScope:inprog] http://errors.angularjs.org/undefined/$rootScope/inprog?p0=%24digest和
app.js (line 48)
Error: $http is not a function
$rootScope.synchronization@http://localhost/task-app/js/app.js:52:20请帮我解决这个问题……我已经添加了$scope,$rootScope,$window,$http,但仍然不适用于我。请看一下我的方案。
发布于 2015-12-31 16:48:29
你可以在你的控制器中定义这个同步函数,我认为你根本不需要使用rootscope。你可以使用这个控制器;
yourApp.controller("yourController", ['$scope', '$http', '$timeout', 'localStorage',
function ($scope, $http, $timeout, localStorage) {
var synchronization = function () {
if (localStorage.getItem('job_id') != "" && localStorage.getItem('job_id') > 0) {
if (localStorage.getItem('job_id.done_tasks') != "" && localStorage.getItem('job_id.done_tasks') > 0) {
$scope.done_tasks = {};
$scope.done_tasks = localStorage.getItem('job_id.done_tasks');
$scope.job_id = localStorage.getItem('job_id');
var userData = $http({
method: "post",
url: "http://localhost/t-app/mobile-data/update-tasks.php",
data: {
done_tasks: $scope.done_tasks,
job_id: $scope.job_id
},
headers: {'Content-Type': 'application/x-www-form-urlencoded'}
});
userData.success(function (userdataobject) {
//* I added response to $scope *//
$scope.status_id = userdataobject["status_id"];
$scope.message = userdataobject["message"];
localStorage.setItem('job_id', '');
localStorage.setItem('job_id.done_tasks', '');
$timeout(synchronization, 2000);
});
}
}
};
}]);刚把你的函数复制到控制器和排列的注入..
注意:我使用超时服务每2秒调用一次这个函数,而不是间隔,你可以根据你的需要进行调整,带出同步函数的线路将在2秒后调用一次。
发布于 2015-12-31 16:50:12
正如我从您的调用中看到的那样,您没有将正确的值传递给函数:
$interval( $rootScope.synchronization, 2000 , 1);
Interval调用您的函数,而同步函数需要四个参数:
$rootScope.synchronization = function($scope, $rootScope, $window, $http){/**/}
您可以像这样传递参数:
$interval( $rootScope.synchronization, 2000 , 1, false, $scope, $rootScope, $window, $http);
请注意上面对$interval的调用中的false。这将确保您走出了解决Error: [$rootScope:inprog]的$apply周期。$interval的文档是here。
另外,我建议将此代码更改为$timeout,因为您只需要这样做一次。此外,你应该使用$window.localStorage而不是localStorage。
编辑2:根据OP的评论,服务将是最好的解决方案:
myApp.factory('SynchronizationService', ['$scope', '$rootScope',
'$window', '$location', '$interval', '$http',
function ($scope, $rootScope, $window, $location, $interval, $http) {
return {
synchronization: function () { /*your code here*/}
};
}]);然后,您可以通过注入服务并调用公开的方法来从控制器调用此方法:
controller('mainCtrl', ['SynchronizationService', function(SyncService) {
SyncService.synchronization();
});https://stackoverflow.com/questions/34543506
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