我正在构建一个带有许多输入验证的类,并决定将它们放在一个__set方法中(我不确定这是否是正确的形式,因为我的OOP经验有限)。这似乎工作得很好,当从类外部传递无效值时抛出适当的错误。但是,如果在类中修改了变量,_ _set方法似乎全部被忽略了。
任何洞察力都将不胜感激。
//RESULT:::::::::::::::::::::::::::::::
// PASS: Testing : hello
// PASS: Testing exception handling
// __SET: Setting b to 123
// PASS: Testing with valid value: 123
// FAIL: Testing exception handling World2
<?php
class Test {
public $a;
private $b;
function __set( $key, $val ) {
switch( $key ) {
case 'b':
if( !is_numeric( $val ) ) throw new Exception("Variable $b must be numeric");
break;
}
echo ( "__SET: Setting {$key} to {$val}<br/>" );
$this->$key = $val;
}
function __get( $key ) { return $this->$key; }
function bMethod() {
$this->b = "World2";
}
}
$t = new Test();
//testing a
try {
$t->a = "hello";
echo "PASS: Testing $a: {$t->a}<br/>";
} catch( Exception $e) {
echo "FAIL: Testing $a";
}
//testing b
try {
$t->b = "world";
echo "FAIL: Testing $b exception handling<br/>";
} catch( Exception $e ){
echo "PASS: Testing $b exception handling<br/>";
}
//testing b with valid value
try {
$t->b = 123;
echo "PASS: Testing $b with valid value: {$t->b}<br/>";
} catch( Exception $e) {
echo "FAIL: Testing $b";
}
//bypassing exception handling with method
try {
$t->bMethod("world");
echo "FAIL: Testing $b exception handling {$t->b}<br/>";
} catch( Exception $e ) {
echo "PASS: Testing $b exception handling<br/>";
}发布于 2009-04-28 18:49:45
阅读__set的定义:"__set()是在向无法访问的成员写入数据时运行的。“无法访问是这里的关键。在类中,所有成员都是可访问的,并且绕过了__set。Overloading
发布于 2009-04-28 18:57:38
php documentation的文档中写道:
__get()用于从无法访问的成员读取数据。
所以,你可以这样做:
<?php
class Test {
private $_params = array();
function __set( $key, $val ) {
...
$this->_params[$key] = $val;
}
function __get( $key ) {
if (isset($this->_params[$key])) return $this->$key;
throw Exception("Variable not set");
}
...
}https://stackoverflow.com/questions/799332
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