在运行下面的代码时,
private static void createAccounts() {
Itil_b__Incident__c[] records = new Itil_b__Incident__c[5];
try {
// create 5 test accounts
for (int i=0;i<1;i++) {
Itil_b__Incident__c a = new Itil_b__Incident__c();
a.setCurrencyIsoCode("USD");
a.setIsDeleted(Boolean.FALSE);
a.setItil_b__Age_Minutes__c(29d);
a.setHas_Managed_Services__c(Boolean.FALSE);
a.setItil_b__Priority_from_ITIL_Matrix__c("Medium");
a.setItil_b__Priority__c("Medium");
a.setItil_b__Description__c("Testing API Descrition");
a.setRank_Zero__c(Boolean.FALSE);
a.setItil_b__Close_With_Problem__c(Boolean.FALSE);
a.setItil_b__Subject__c("Test from API");
a.setItil_b__Origin__c("Phone");
a.setItil_b__Age__c("29 Days");
a.setItil_b__Status__c("New");
a.setAssigned_for_Today__c(Boolean.FALSE);
a.setItil_b__Urgency__c("P4 - Low");
a.setItil_b__Category__c("Request");
a.setItil_b__Impact__c("Low");
a.setSeverity__c("Sev4");
records[i] = a;
}
// create the records in Salesforce.com
SaveResult[] saveResults = connection.create(records);
// check the returned results for any errors
for (int i=0; i< saveResults.length; i++) {
if (saveResults[i].isSuccess()) {
System.out.println(i+". Successfully created record - Id: " + saveResults[i].getId());
} else {
Error[] errors = saveResults[i].getErrors();
for (int j=0; j< errors.length; j++) {
System.out.println("ERROR creating record: " + errors[j].getMessage());
}
}
}
} catch (Exception e) {
e.printStackTrace();
}
}我在saveResults行中得到以下错误,
[InvalidSObjectFault [ApiQueryFault [ApiFault exceptionCode='INVALID_TYPE'
exceptionMessage='Must send a concrete entity type.'
]
row='-1'
column='-1'
]
]我正在通过Java API在自定义sObject Itil_b__Incident__c中创建一个新记录,您能帮助我可能遗漏的内容吗?
发布于 2015-12-17 23:54:25
检查您的for循环。你现在有了for (int i = 0; i < 1; i++) {,你的评论说你想创建5个对象,所以它应该是for (int i=0; i<5; i++) {。
通常在我的例子中,我需要将我的对象序列化为JSON,因为我使用的是REST API。
https://stackoverflow.com/questions/34337722
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