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在创建CriteriaQuery时需要帮助
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Stack Overflow用户
提问于 2015-12-16 22:32:40
回答 1查看 24关注 0票数 0

首先,我想知道是否有可能这样做?

下面是我的查询,我正在尝试使用标准进行构建。

代码语言:javascript
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SELECT CONCAT('record-', rl.record_id) AS tempId, 
        'sloka' AS type, 
         rl.record_id AS recordId,
         rl.title AS title, 
         rl.locale as locale,
         rl.intro AS intro, 
         rl.title AS localetitle, 
         NULL AS audioUrl,
         lp.name AS byName,
         lp.person_id AS byId,
         lp.name AS onName,
         lp.person_id AS onId

    FROM record_locale rl 
        LEFT JOIN record r ON rl.record_id = r.record_id 
        LEFT JOIN locale_person lp ON r.written_on = lp.person_id 
    WHERE rl.title LIKE :title 
        AND rl.locale = :locale 
        AND lp.locale = :locale 

UNION 

SELECT CONCAT('lyric-', s.song_id) AS tempId, 
        'bhajan' AS type,
        s.song_id AS recordId,
        s.title, 
        l.locale as locale,
        NULL AS intro,
        l.title AS localetitle,
        s.audio_url AS audioUrl,
        lpb.name AS byName,
        lpb.person_id AS byId,
        lpo.name AS onName,
        lpo.person_id AS onId 

    FROM song s 
        LEFT JOIN locale_person lpb 
    ON (s.written_by = lpb.person_id AND lpb.locale = :locale) 
        LEFT JOIN locale_person lpo
    ON (s.written_on = lpo.person_id AND lpo.locale = lpb.locale)
        INNER JOIN lyric l 
    ON (l.locale = lpb.locale AND l.song_id = s.song_id) 

    WHERE s.title LIKE :title AND s.approved_by IS NOT NULL 

    ORDER BY localeTitle ASC

// END

根据几个条件,我可能需要两个查询的联合,或者只有单个查询而不联合。

EN

回答 1

Stack Overflow用户

发布于 2015-12-16 22:40:51

将SQL转换为JPQL通常是很好的第一步,因为我们不太清楚这些表映射到什么,或者您希望得到什么。如果在JPQL中可以做到这一点,那么条件查询也应该是可能的。除了这种情况: JPA/JPQL没有联合运算符,所以它不能直接在JPA中工作,但一些提供者,如EclipseLink,有支持。请参见:

UNION to JPA Queryhttp://www.eclipse.org/eclipselink/documentation/2.5/jpa/extensions/j_union.htm

票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/34314676

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