替换并获取单词出现次数

Question

我有一个字符串，我想替换特定的单词，还想计算出现的次数。e.g

"Of course, there are many other open source or commercial tools available.
Twitter typeahead is probably the most important open source alternative."
.replace(/source/g,'<b>source</b>');

这将用<b>source</b>替换所有的source，但我想要source出现的计数，也就是2。

Answer 1

在调用replace之前，您可以简单地执行以下操作：

​

var count = ("Of course, there are many other open source or commercial tools available.    Twitter typeahead is probably the most important open source alternative.".match(/source/g) || []).length;
var replaceString = "Of course, there are many other open source or commercial tools available.Twitter typeahead is probably the most important open source alternative."
.replace(/source/g,'<b>source</b>');
alert(count);
alert(replaceString);

​

Answer 2

function replaceAndCount(str, tofind, rep){

   var _x = str.split(tofind);
   return{
     "count":_x.length-1,
     "str":_x.join(rep)
   };

}

类似这样的函数。

现在计数将会是

var str = "Of course, there are many other open source or commercial tools available.
Twitter typeahead is probably the most important open source alternative.";
var count = replaceAndCount(str, "source", "<b>source</b>").count;

并且新的字符串将是

var newString = replaceAndCount(str, "source", "<b>source</b>").str.

Answer 3

为什么不拆分并加入呢？

function replaceAndCount( str, toBeReplaced, toBeReplacedBy )
{
  var arr = str.split( "toBeReplaced" );

  return [ arr.join( toBeReplacedBy  ), arr.length ];
}  

replaceAndCount( "Of course, there are many other open source or commercial tools available. Twitter typeahead is probably the most important open source alternative." , "source", "<b>source</b>");