如何在tableViewCell中运行imagePicker

Question

我有个带手机的tableView。在这个单元格中，我有一个imageView，并有一个覆盖它的按钮。该按钮有一个IBAction。当被点击时，这个按钮应该会召唤imagePicker。IBAction代码位于单元格子视图中。

@IBAction func MyStatusImageButtonAction(sender: AnyObject) {
    // Select Image
    let imagePicker = UIImagePickerController()
    imagePicker.delegate = self
    imagePicker.sourceType = UIImagePickerControllerSourceType.PhotoLibrary
    imagePicker.allowsEditing = false
    self.presentViewController(imagePicker, animated: true, completion: nil)

因为这一行，我得到了一个错误。

self.presentViewController(imagePicker, animated: true, completion: nil)

错误说明"myCell“类型的"Value”没有成员"presentViewController“。

我是否应该将imagePicker加载到托管该单元的viewController中，然后以某种方式将其传输到该单元？我是不是应该用不同的代码加载单元中的imagePicker？我说的全错了吗？

为了清楚起见，我的目标是让用户加载此TableViewController，并且能够仅将图像分配给此单元中的imageView。

谢谢。

Answer 1

编写一个协议，您的TableViewController将为您显示它。

protocol ImagePickerDelegate {

    func pickImage()
}

在你的牢房里

var delegate : ImagePickerDelegate?

@IBAction func pickImage(sender: AnyObject) {

    delegate?.pickImage()
}

在你的tableViewController中

override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {

    let cell = tableView.dequeueReusableCellWithIdentifier("displayImage", forIndexPath: indexPath) as! ImageTableViewCell

    cell.delegate = self

    return cell
}

func pickImage() {

    let imagePicker = UIImagePickerController()
    imagePicker.delegate = self
    imagePicker.sourceType = UIImagePickerControllerSourceType.PhotoLibrary
    imagePicker.allowsEditing = false
    self.presentViewController(imagePicker, animated: true, completion: nil)
}

func imagePickerController(picker: UIImagePickerController, didFinishPickingImage image: UIImage, editingInfo: [String : AnyObject]?) {

    dismissViewControllerAnimated(true, completion: nil)

    var cell = tableView.cellForRowAtIndexPath(NSIndexPath(forRow: 0, inSection: 0)) as! ImageTableViewCell
    cell.displayImageView.image = image
}

希望这能有所帮助。

Answer 2

只有一个viewController才能呈现另一个viewController。所以使用：

self.view.presentViewController(imagePicker, animated: true, completion: nil)

Answer 3

只是@truongky关于Swift 5语法更新的帖子的后续文章。

正如他正确地指出的那样，首先要创建一个协议。您可以为您的协议创建一个扩展名为的新文件。然后插入OP识别的代码：

protocol ImagePickerDelegate {
    func pickImage() 
}

然后，在您的TableViewController中：

func pickImage() {
    let imagePicker = UIImagePickerController()
    imagePicker.delegate = self
    imagePicker.sourceType = UIImagePickerController.SourceType.photoLibrary
    imagePicker.allowsEditing = false
    self.present(imagePicker, animated: true, completion: nil)
}

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [UIImagePickerController.InfoKey : Any]) {
    if let image = info[UIImagePickerController.InfoKey.originalImage] as? UIImage {
        let cell:ImageCell = tableView.cellForRow(at: IndexPath(row: 0, section: 0)) as! ImageCell
        cell.customImage.image = image
    }

    picker.dismiss(animated: true, completion: nil)
}

此外，您还可以修改自定义单元格以响应点击手势识别器，如下所示：

var delegate : ImagePickerDelegate?

@IBOutlet weak var customImage: UIImageView!

override func awakeFromNib() {
    super.awakeFromNib()
    // Initialization code

    addTapGestureRecognizer(for: customImage)
}

override func setSelected(_ selected: Bool, animated: Bool) {
    super.setSelected(selected, animated: animated)

    // Configure the view for the selected state
}

func addTapGestureRecognizer(for view: UIImageView) {
    let tap = UITapGestureRecognizer(target: self, action: #selector(pickImage))
    tap.numberOfTapsRequired = 1
    view.isUserInteractionEnabled = true
    view.addGestureRecognizer(tap)
}

@objc func pickImage() {
    delegate?.pickImage()
}

希望这能有所帮助。

功劳~