假设我有下表:
ID Apple Orange Banana
1 Y Y N
2 N Y N
3 Y N N
4 Y N Y我应该如何在plsql中编写查询,这将给我带来以下结果?
ID Apple Orange Banana
Y 3 2 1
N 1 2 3发布于 2015-12-09 11:01:58
下面是一个使用条件聚合的方法:
select x.id,
sum(case when apple = x.id then 1 else 0 end) as Apple,
sum(case when orange = x.id then 1 else 0 end) as Orange,
sum(case when banana = x.id then 1 else 0 end) as Banana
from t cross join
(select 'Y' as id from dual union all
select 'N' from dual
) x
group by x.id;发布于 2015-12-09 11:19:46
SELECT 'Y' id,
SUM(DECODE(apple,'Y',1)) apple_cnt,
SUM(DECODE(Orange,'Y',1)) Orange_cnt,
SUM(DECODE(Banana,'Y',1)) Banana_cnt
FROM
(SELECT '1' ID, 'Y' Apple, 'Y' Orange, 'N' Banana FROM dual
UNION ALL
SELECT '2' , 'N', 'Y', 'N' FROM dual
UNION ALL
SELECT '3' , 'Y' , 'N' , 'N' FROM dual
UNION ALL
SELECT '4' , 'Y' , 'N' , 'Y' FROM dual
)
UNION ALL
SELECT 'N' id,
SUM(DECODE(apple,'N',1)) apple_cnt,
SUM(DECODE(Orange,'N',1)) Orange_cnt,
SUM(DECODE(Banana,'N',1)) Banana_cnt
FROM
(SELECT '1' ID, 'Y' Apple, 'Y' Orange, 'N' Banana FROM dual
UNION ALL
SELECT '2' , 'N', 'Y', 'N' FROM dual
UNION ALL
SELECT '3' , 'Y' , 'N' , 'N' FROM dual
UNION ALL
SELECT '4' , 'Y' , 'N' , 'Y' FROM dual
)发布于 2016-01-03 04:40:45
如果表的结构不是必须的,我建议你这样结构:
ID FRUIT FLAG
1 Apple Y
2 Apple Y
3 Apple Y
4 Apple N
5 Orange N
6 Orange N
7 Orange N
8 Orange Y
9 Orange Y
10 Banana Y
11 Banana N
12 Banana Y
13 Banana Y
14 Banana N对于此设计,您可以使用Pivot Query
SELECT *
FROM (SELECT Fruit, Flag FROM tab1) PIVOT (COUNT (Fruit)
FOR (fruit)
IN ('Apple' AS Apple,
'Orange' AS Orange,
'Banana' AS Banana))结果:
FLAG APPLE ORANGE BANANA
Y 3 2 3
N 1 3 2另一种变体:
SELECT *
FROM (SELECT Fruit, Flag FROM tab1) PIVOT (COUNT (Flag)
FOR (Flag)
IN ('Y' AS Yes, 'N' AS No))结果:
FRUIT YES NO
Apple 3 1
Orange 2 3
Banana 3 2https://stackoverflow.com/questions/34169987
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